Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Source. Published p. 263, Theorem 1.9, and p. 274 (PDF).
Statement. For each fixed integer , there are and such that, if , and , then contains distinct members with for every . Only the intersection cardinalities must agree; their actual sets need not coincide.
Proof. For , Theorem 1.1 supplies the assertion for a fixed small window around . Suppose it holds for . Apply Theorem 1.7 with output loss , and choose the new input loss small enough for that theorem. Choose the new window inside both its window and the inductive window. It gives at least ordered target pairs. Thus some has a neighbor family
of size at least . Remove itself if present. For sufficiently large the remaining size is still at least , since . The induction gives distinct members of this family with all mutual intersection sizes . Together with they give the required members. Increase to cover all thresholds used.
Scope. The eventual threshold is explicit. The source introduction omits it, but its proof uses Theorem 1.7 in its large- range. For arbitrary fixed , an assertion for every would even allow a full cube with fewer than members. The removal of handles the possible diagonal pair without assuming its size differs from .
Dependencies. theorem_1_1, theorem_1_7.