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Source. Corollary 10, p. 14, with its proof on the same page, of David Ellis, Irredundant families of subcubes, arXiv:1003.2960v1 (2010), published in Mathematical Proceedings of the Cambridge Philosophical Society 150(2) (2011), 257–272, as identified on the source card. Labels and pages are those of arXiv:1003.2960v1.

Statement

Notation as on the Theorem 8 page.

Corollary 10 (p. 14). Let n≤2kn\le2k. If A\mathcal A is an irredundant family of kk-subcubes of {0,1}n\{0,1\}^n which contain 0\mathbf 0 or 1\mathbf 1, then ∣A∣≤(nk)|\mathcal A|\le\binom nk.

This is the result the abstract and introduction (pp. 1, 3–4) state for k≥n/2k\ge n/2. It is the bound of Conjecture 1 (Aharoni–Holzman, p. 2) for the special families whose members all pass through 0\mathbf 0 or 1\mathbf 1, and it also covers k=n/2k=n/2, which the conjecture excludes. Extremal families are not unique even for n=5n=5, k=3k=3 (pp. 14–15).

Proof pointer

Page 14: induction on nn with the codimension n−kn-k fixed, starting from Theorem 8 at n=2kn=2k. Given a family of (k+1)(k+1)-subcubes of {0,1}n+1\{0,1\}^{n+1} through 0\mathbf 0 or 1\mathbf 1, the members in which coordinate ii moves project, by deleting that coordinate, to an irredundant family of kk-subcubes of {0,1}n\{0,1\}^n through 0\mathbf 0 or 1\mathbf 1, so there are at most (nk)\binom nk of them; each member moves in k+1k+1 coordinates, and double counting gives ∣A∣≤n+1k+1(nk)=(n+1k+1)|\mathcal A|\le\frac{n+1}{k+1}\binom nk=\binom{n+1}{k+1}.

Dependencies

Theorem 8.

Read depth. Claims checked: the statement on p. 14 was read clause by clause. The proof on the same page was read but not checked step by step.

Bears on

No Erdős problem.