Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Corollary (p. 421, unnumbered). Let points be given in the real projective plane, not all on a line, and join every two of them. Then the number of distinct lines so obtained is at least , and equality holds only if of the points are on a line.
The paper presents this as Theorem 1 read for points and their connecting lines, and says it can also be proved independently through Gallai's theorem (see the page on Gallai's theorem). Its footnote 2 (p. 421) adds that the corollary had also appeared as a problem in the American Mathematical Monthly.
Source. N. G. de Bruijn and P. Erdős, On a combinatorial problem, Nederl. Akad. Wetensch., Proc. 51 (1948), 1277--1279 = Indag. Math. 10 (1948), 421--423, in the Indagationes page numbering: the corollary on p. 421, its independent proof on p. 422. The edition read is identified on the source card.
Read depth. Claims checked: the statement was read clause by clause on the printed page, and the induction on p. 422 was read. Nothing here is independently reviewed.
Proof pointer
Two routes are given. The first is Theorem 1 applied to the points with the lines as the sets: each pair of points lies on exactly one line, and there is more than one line since the points are not collinear. For the equality case, the theorem's second alternative with would put at least three of the points on every line, which Gallai's theorem forbids, and with it is three non-collinear points, already of the form on a line. The paper does not spell this step out; it is an observation of this page. The second route (p. 422) is an induction on : take a line through exactly two points , which Gallai's theorem provides; if are collinear the lines are visible directly, and otherwise they determine at least lines by induction, none of which is the line . The same induction gives the equality case.
Dependencies
Theorem 1 for the first route; Gallai's theorem for the second.