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Statement
Setting (p. 3). Let be a graph whose vertex set is split as . For a vector , is the random induced subgraph in which contains each vertex independently with probability . All of is kept.
Lemma 4 (p. 3). For every there is with the following property. Let be a graph with vertex partition , where . Let and be such that every two distinct satisfy both
Then some makes have at least distinct degrees.
The statement gives no bound on , so it says nothing about the size of the induced subgraph beyond .
Source. M. Jenssen, P. Keevash, E. Long and L. Yepremyan, Distinct degrees in induced subgraphs, Proc. Amer. Math. Soc. 148 (2020), no. 9, 3835--3846, DOI 10.1090/proc/15060; read in arXiv:1910.01361v1, Lemma 4 and the definition of in subsection 2.1, p. 3; the proof on p. 4. The edition read is recorded on the source card; the lemma number and pages are the preprint's.
Read depth. Claims checked: the setting and the statement were read clause by clause on the page image of p. 3. The proof (p. 4) was read for its structure, not checked step by step.
Proof pointer
Subsection 2.1 (pp. 3--4). A vertex of typically has degree in within of its expectation. Two such vertices can then share a degree only if their expected degrees differ by at most , and the separation hypothesis bounds the number of such pairs by . Each pair has equal degrees with probability , by the diversity hypothesis and Proposition 5. Two applications of Markov's inequality give one outcome in which at least half of is near its expectation and only pairs collide. Turán's theorem (Theorem 6) then gives the vertices with distinct degrees.
Dependencies
Proposition 5 (p. 4), which the paper deduces from Erdős's bound on the Littlewood--Offord problem (the paper's [7]), and Turán's theorem in the form of Theorem 6 (p. 4).
Bears on
- Problem 637: a step in the proof of Theorem 2, and so of Theorem 1. The problem page's remark that the proof of Theorem 2 yields an induced subgraph on a constant fraction of the vertices is drawn from that proof (subsection 2.3, p. 6) and from the proof of this lemma (p. 4), not from the statement above, which fixes no size for ; that remark is the problem page's own and is not reviewed here.