Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Notation (printed p. 633): for a fixed graph and an integer , is the largest for which the edges of can be colored with colors without a copy of in whose edges all have different colors; and are the path and the cycle on vertices. A subgraph with no two edges of the same color is "totally multicoloured" (TMC, p. 634). The site's is this .
Conjecture 1 (printed p. 636).
"The conjecture says that the best way to colour so that no TMC would occur is to divide the points into groups of vertices and then colour all the edges joining vertices of the same group by different colours, and the edges joining vertices from different groups colour by further colours in the following way: the vertices of the -th group are joined by the -th extra colour to the vertices of the -th group if . We do not assert, however the uniqueness of the extremal colourings. This conjecture will be proved only for in Theorem 5." (pp. 636–637, as printed; Theorem 5 on p. 637 is stated for Conjecture 2, the path conjecture, so the cross-reference does not match the theorem it names. The case is proved in part A of the Appendix (p. 642), which opens "Here we prove Conjecture 2 for " but proves , the triangle case of Conjecture 1. The site records with "a simple proof" from this paper.)
Remark 2 (p. 636) places the cycle and path problems: when in Theorem 1 "the information yielded by Theorem 1 is that ... This case will be called degenerated", and "Two degenerated problems will be discussed here: the problems of and ."
Source. P. Erdős, M. Simonovits and V. T. Sós, Anti-Ramsey theorems, Infinite and finite sets (Colloq., Keszthely, 1973), Vol. II, Colloq. Math. Soc. János Bolyai 10, North-Holland (1975), 633–643; printed pp. 636–637 = PDF pp. 4–5 of the Rényi archive scan, with the notation on printed p. 633 = PDF p. 1 and part A of the Appendix on printed p. 642 = PDF p. 10, read on the page images (the OCR text layer garbles every formula). The edition is identified in the source digest.
Read depth. Claims checked: the conjecture, the description of the coloring, the two sentences after it and Remark 2 were read clause by clause on the page images, as was part A of the Appendix (p. 642) with its short proof of the case . A conjecture; the paper proves nothing about for .
Proof pointer
For , part A of the Appendix (p. 642). With colors, one edge of each color gives edges on vertices, hence a cycle, and that cycle is totally multicolored. A shortest totally multicolored cycle with would yield a shorter one, since the color of the chord lies on at most one of the two arcs it closes, so a totally multicolored triangle exists. Coloring each edge with by uses colors and leaves no totally multicolored cycle, so . For the paper has no proof. The cycle case was settled by Montellano-Ballesteros and Neumann-Lara, Graphs Combin. 21 (2005), 343--354, which is filed as montellano_ballesteros_neumann_lara_2005_anti_ramsey_theorem_cycles. Their Theorem 5 (printed p. 352), for every with , yields this conjecture as its Corollary 1 (printed p. 353, where the printed sign differs from the plus sign of the conjecture, read there as a misprint). That page records the two statements read clause by clause on the page images and the proof read in the text layer for structure only, with nothing independently reviewed. This page's own standing is unchanged: the 1975 paper proves nothing about for .
Dependencies
None.
Bears on
- Problem 1105: the first question of the problem, verbatim (the site's is the paper's ).