Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Setting (Section 2, p. 47). Let be distinct integers with , and let be the remaining integers of the interval (the complement of the among the integers up to ).
Question (p. 47). Is there always an integer for which the number of solutions of is at least ? The paper says it could not decide this, and notes that the choice , , shows that would be best possible.
Theorem (p. 47). There is always an integer for which the number of solutions of is at least .
Reported result (p. 47). Scherk (the paper's reference [3]) proved that for a suitable the number of solutions is at least .
The English summary (p. 48) states the theorem as: "I show that there exists an integer so that there are at least 's among the integers . Scherk improved this to . It is not known whether this can further be improved to ."
Proof pointer
Averaging (p. 47): over the shifts the equation has solutions in all, one for each pair , and there are fewer than shifts, so some shift carries at least of them.
Read depth. Claims checked: the setting, the question, the theorem, the example and Scherk's bound were read clause by clause on the page images of pp. 47 and 48; the averaging was re-derived here.
Source. P. Erdős, Some remarks on number theory (in Hebrew), Riveon Lematematika 9 (1955), 45--48; the edition read is named on the source card.
Dependencies
None.
Bears on
- Problem 36: with , the and form a partition of into two halves of size , and the count of solutions of is the problem's count of differences (the problem counts , which is the same quantity with the halves' names exchanged). In the problem's normalization the theorem is , Scherk's bound is , and the paper's question asks whether is admissible, which the example shows would be optimal; the paper poses this as a question it could not decide, not as a conjecture. The paper treats only totals , that is even , and proves nothing beyond the bound .