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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (p. 113). f(n)f(n) is the number of solutions of 2k+p=n2^k+p=n with pp prime, as for Theorem 1, which gives f(n)>clog⁡log⁡nf(n)>c\log\log n for infinitely many nn.

(a) The upper bound (p. 115, quoted). "It can be conjectured that f(n)=o(log⁡n)f(n)=o(\log n)." The paper adds that this, if true, is probably rather deep.

(b) The integers n−2kn-2^k (p. 115). The paper cannot prove that, for all sufficiently large nn, the integers

n−2k,1≤k<log⁡nlog⁡2(8)n-2^k,\qquad 1\le k<\frac{\log n}{\log2} \qquad (8)

are not all prime. For n=105n=105 all of them are prime; the paper reports from the prime tables that no other nn in 105<n≤3⋅52⋅11⋅13⋅19=203775105<n\le3\cdot5^2\cdot11\cdot13\cdot19=203775 has this property, and states (quoted) "It seems likely that 105 is the largest exceptional integer."

(c) A generalization of Theorem 1 (p. 115). Erdős believes the following holds: for every constant cc and every sufficiently large nn, if a1<a2<⋯<ax≤na_1<a_2<\cdots<a_x\le n with x>log⁡nx>\log n, then some mm has more than cc representations m=p+aim=p+a_i. The paper calls this a generalization of Theorem 1.

Scope

These are problems the paper poses; it proves none of them. Statement (a) is the pointwise bound that Theorem 1 complements from below; Theorem 2 bounds ff only on average.

Read depth. Claims checked: the three statements were read clause by clause on p. 115 of the print, and the product $3\cdot5^2\cdot11\cdot13\cdot19 =203775$ was checked.

Source. P. Erdős, On integers of the form 2k+p2^k+p and some related problems, Summa Brasil. Math. 2 (1950), fasc. 8, 113--123; the edition read is named on the source card.

Bears on

  • Problem 236: statement (a) is the problem's question, posed here as a conjecture; the paper proves nothing on it.
  • Problem 1142: statement (b), with 1≤k<log⁡n/log⁡21\le k<\log n/\log2, ranges over the same powers 1<2k<n1<2^k<n as the problem. The paper records 105105 and a search to 203775203775 and conjectures that 105105 is the largest such nn, which is the problem's question whether any n>105n>105 exists; it proves nothing on it.
  • Problem 237: statement (c) is a form of the problem's question for finite sets, with the hypothesis x>log⁡nx>\log n in place of the problem's $\lvert A\cap{1,\ldots,N}\rvert\gg \log N$; the paper calls it a generalization of Theorem 1, which treats the powers of 22, and proves nothing on it beyond that theorem.