Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Section 8, "Future Prospects" (p. 20), lists (C1)--(C5) as samples of the "easier" problems that the analysis of the problem has produced and that it says remain unsolved; the two below concern the function itself ((C3) concerns the function, (C4) and (C5) permutations given by generalized Collatz functions).
(C1) (Finite Cycles Conjecture), quoted: "Does the function have finitely many cycles (i.e. finitely many purely periodic orbits on the integers)? This is conjectured to be the case."
(C2) (Divergent Trajectories Conjecture-1), quoted: "Does the function have a divergent trajectory, i.e., an integer starting value whose iterates are unbounded? This is conjectured not to be the case."
The open problem on (p. 20, unlabeled). Let be the number of integers less than that reach under the iteration. The survey recalls that by Krasikov and Lagarias (its [57]) there is a positive constant with , and states as open the problem of showing that for each there is a positive constant with . (The same paper is cited for (W5) of Section 6 in the form "at least , for all sufficiently large ".)
Source. J. C. Lagarias, The problem: an overview, in The Ultimate Challenge: The Problem (AMS, 2010), 3--29; the arXiv:2111.02635v1 copy, p. 20, read on the page image. The edition read is identified on the source card.
Read depth. Claims checked: the statements were read clause by clause on the page image. They are open problems; nothing here is independently reviewed.
Proof pointer
None: the statements are open. The bound is Krasikov and Lagarias, Acta Arith. 109 (2003), 237--258, whose source card is krasikov_lagarias_2003_bounds_difference_inequalities.
Dependencies
Krasikov and Lagarias 2003 (the survey's [57]), as reported.
Bears on
- Problem 1135: (C1) and (C2) range over all integers, the problem over the positive integers. An affirmative answer to the problem would show that on the positive integers is the only cycle of and no trajectory is unbounded, which is the positive-integer part of (C1) and (C2); it would not settle either as printed, and neither conjecture, nor both together, would answer the problem. An affirmative answer would make count every positive integer below , so the open problem on is a weak consequence of it; the survey proves none of these.