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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (p. 17). TT is the 3x+13x+1 function, T(n)=(3n+1)/2T(n)=(3n+1)/2 for odd nn and T(n)=n/2T(n)=n/2 for even nn, on all integers ((1.2), p. 2). For an integer aa, Definition 2.10 sets πa(x)\pi_a(x) to be the number of integers nn with ∣n∣≤x|n|\le x such that T(k)(n)=aT^{(k)}(n)=a for some k≥0k\ge0. Definition 2.11 sets

η3+(a)=lim sup⁡x→∞log⁡πa(x)log⁡x,η3−(a)=lim inf⁡x→∞log⁡πa(x)log⁡x,\eta_3^+(a)=\limsup_{x\to\infty}\frac{\log\pi_a(x)}{\log x},\qquad \eta_3^-(a)=\liminf_{x\to\infty}\frac{\log\pi_a(x)}{\log x},

and, when the two agree, calls the common value the 3x+13x+1 growth exponent η3(a)\eta_3(a). For a≡0(mod3)a\equiv0\pmod 3 the inverse orbit of aa is {2ka:k≥0}\{2^ka:k\ge0\}, so η3(a)=0\eta_3(a)=0.

Conjecture 2.1 (p. 17, 3x+13x+1 Growth Exponent Conjecture), quoted: "For all integers a≢0(mod3)a\not\equiv 0 \pmod 3, the 3x+13x+1 growth exponent η3(a)\eta_3(a) exists, with η3(a)=1\eta_3(a)=1."

The survey attributes the conjecture to Applegate and Lagarias, and adds (p. 18) that the 3x+13x+1 Conjecture would imply η3(1)=1\eta_3(1)=1 but does not seem to determine η3(a)\eta_3(a) for every such aa; that Applegate and Lagarias also conjectured the stronger linear bound πa(x)>cax\pi_a(x)>c_ax for all x≥1x\ge1, with a constant ca>0c_a>0; that Theorem 2.5 (Krasikov and Lagarias: πa(x)≥x0.84\pi_a(x)\ge x^{0.84} for x≥x0(a)x\ge x_0(a), p. 17) gives η3−(a)≥0.84\eta_3^-(a)\ge0.84; and that the branching random walk model of §6.5 predicts η3(a)=1\eta_3(a)=1 (see Theorem 6.5).

Source. A. V. Kontorovich and J. C. Lagarias, Stochastic models for the 3x+13x+1 and 5x+15x+1 problems, arXiv:0910.1944v1 (2009), 66 pp.; published in The Ultimate Challenge: The 3x+13x+1 Problem (AMS, 2010). Pages and labels are those of the arXiv v1 print; the edition read is identified on the source card.

Proof pointer

None: the statement is a conjecture. The lower bound behind η3−(a)≥0.84\eta_3^-(a)\ge0.84 is Krasikov and Lagarias, Acta Arith. 109 (2003); the survey says the exponent was computed with k=9k=9 (p. 17), while that paper's own result page, Theorem 6.1, records a computation with k=11k=11.

Read depth

Claims checked: Definitions 2.10 and 2.11, Conjecture 2.1 and the remarks on p. 18 were read clause by clause on the page images of the print. Nothing here is independently reviewed.

Dependencies

Theorem 2.5 of the survey (Krasikov and Lagarias 2003), as reported, for the lower bound 0.840.84.

Bears on

  • Problem 1135: the problem's ff is the survey's TT on the positive integers. An affirmative answer to the problem puts every positive integer up to xx into the count π1(x)\pi_1(x), and π1(x)≤2x+1\pi_1(x)\le2x+1, so it gives η3(1)=1\eta_3(1)=1, as the survey notes (p. 18). The converse does not follow: η3(1)=1\eta_3(1)=1, or Conjecture 2.1 for every aa, leaves room for positive integers that never reach 11, so neither would answer the problem. The survey proves neither.