Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Setting: the notation of Lemma 5 (, , , and the rotation class ), and the right shift on (p. 12; the print ends the image tuple with ).
Lemma 9 (p. 12). Let with , let , and suppose . Then
and in particular
The displays are (14) and (15).
Reformulation (p. 13). The paper concludes from Lemma 9 that the negation of (A), the statement that is the only Collatz cycle in (p. 1), is equivalent to
(A) there exists a non-periodic , , with .
The paper gives this equivalence in one sentence, without a separate proof. It offers it (p. 12) as the kind of number-theoretic argument it thinks is needed for (A), since the minimum of rational cycles grows at least linearly in their length (Remark 1, p. 8) and bounds of the kind in Theorem 4 therefore cannot prove (A).
Source. Lorenz Halbeisen and Norbert Hungerbühler, Optimal bounds for the length of rational Collatz cycles, Acta Arith. 78 (1997), 227--239; Lemma 9 on p. 12, its proof on pp. 12--13 and (A) on p. 13 of the authors' preprint named on the source card, numbered 1--13 rather than by the journal's pagination.
Read depth. Claims checked: the statement, the formulas (13) and the reformulation (A) were read on the print, and the proof on pp. 12--13 was read. Nothing here is independently reviewed.
Proof pointer
Pages 12--13. From (4), and (13). For the integrality of shows that , so the gcd of with that number equals , which is (14). A rotation ending in only doubles under , and following the rotation class around gives (15).
Dependencies
The decomposition formula (4) (p. 3) and the definition (2) of (p. 2).
Bears on
- #1135: background only. A cycle of the problem's in the positive integers other than would answer the problem in the negative; (A) restates the existence of such a cycle as a divisibility condition on and decides nothing about it.