Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Item 6 of the new-problems half (printed p. 150, in Hungarian): let be an arbitrary sequence and the sequence of those numbers that are multiples of at least one ("azon számok sorozata, melyek legalább egy -nak többszörösei"). Is it true that for every
In translation: "(1), if true, clearly cannot be improved: let the sequence consist only of , , . We may also remark that there is no for which holds for every sequence and ": take the 's to be the numbers between and and large; if then . The item cites Erdős, Note on sequences of integers no one of which is divisible by any other, J. London Math. Soc. 10 (1935), 126--128.
So the 1966 paper defines as the count of multiples (), the site's reading of Problem 488; the 1961 problem paper prints the count of non-multiples at its item (I.27.1) (printed p. 236; filed as erdos_1961_unsolved_problems).
Source. P. Erdős, Számelméleti megjegyzések, V. Extremális problémák a számelméletben, II, Mat. Lapok 17 (1966), 135--155; item 6 on printed p. 150 (PDF p. 16 of the Rényi archive's 21-page scan), read on the page image.
Read depth. Claims checked: the definition, display (1), the single-element example and the reverse-inequality remark were read clause by clause on the page image. A question with two elementary remarks; no proof.
Proof pointer
None; a question. The two remarks are elementary: for the single set with and , and , so , and no constant below works in (1); the reverse example follows from the multiples of the numbers in thinning out.
Dependencies
None (a question).
Bears on
- Problem 488: the problem's statement in the 1966 wording with the count of multiples, and the sharpness example the site's page records; the 1961 paper's item prints the opposite divisibility condition.