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Statement

Let GG be an abelian group of nn elements, HH its set of elements, and for A⊂HA\subset H put A∗={∑εiai:ai∈A, εi=0 or 1 but not all εi are 0}A^*=\{\sum\varepsilon_ia_i:a_i\in A,\ \varepsilon_i=0\text{ or }1\text{ but not all }\varepsilon_i\text{ are }0\} (p. 227). Theorem (p. 227). "There exist a real number c>0c>0 and an integer n0n_0 such that for every n>n0n>n_0, for every GG, and for every A⊂HA\subset H, ∣A∣≥cn|A|\ge c\sqrt n"

0∈A∗.0\in A^*.

The introduction (p. 227) states the conjecture being proved as Erdős and Heilbronn's, "F(k)>0F(k)>0 if k>cnk>c\sqrt n (cc is an absolute constant)", with F(k)F(k) the number of representations of the unit element as a product of a subset of kk distinct elements; records Ryavec's earlier bound k>36n⋅exp⁡(clog⁡n/log⁡log⁡n)k>3\sqrt{6n}\cdot\exp(c\sqrt{\log n}/\log\log n); and adds "They further conjectured that F(k)>0F(k)>0 if k>2nk>2\sqrt n and that it is not necessary to assume that GG is Abelian. At present I can not decide these conjectures." An editor's footnote says the first conjecture was proved for prime nn and certain other cases by Olson [3], [4].

Source. E. Szemerédi, On a conjecture of Erdős and Heilbronn, Acta Arith. 17 (1970), no. 3, 227--229, DOI 10.4064/aa-17-3-227-229 (received 15 May 1969). The retained file has two pages: the first carries the issue's contents page and printed p. 227, the second printed pp. 228--229; it has no text layer and was read on the page images (its identity and completeness against the printed pagination were checked there).

Read depth. Claims checked: the definitions, the Theorem, the introduction's attributions and the closing remark on the Eggleston--Erdős problem (p. 229) were read clause by clause on the page images. The two-page proof (pp. 228--229) was read for its structure only.

Proof pointer

The proof (p. 228) opens by assuming condition (1) and showing that it forces 0∈A∗0\in A^*. Condition (1) asks for c>100c>100, a set DD with 14cn<∣D∣<34cn\tfrac14c\sqrt n<|D|<\tfrac34c\sqrt n and l>3nl>3\sqrt n pairs Ai,Bi⊂AA_i,B_i\subset A with Ai−D={ai}A_i-D=\{a_i\}, D−Bi={bi}D-B_i=\{b_i\} and ∣Ai∗−D∗∣,∣D∗−Bi∗∣≤n|A_i^*-D^*|,|D^*-B_i^*|\le\sqrt n; from the matrix mik=d−bi+akm_{ik}=d-b_i+a_k with d=∑a∈Dad=\sum_{a\in D}a one finds an entry that is simultaneously a subset sum of a BiB_i and of the form d−bi+aqd-b_i+a_q, forcing 0∈A∗0\in A^*. It remains to produce (1); the paper does this through the relation X={(U,V):U⊂V,∣V−U∣=1,∣V∗−U∗∣≤n}X=\{(U,V):U\subset V,|V-U|=1,|V^*-U^*|\le\sqrt n\} (display (3)): a counting condition (4) on the pairs in XX gives (5), which gives (1), and (4) is proved by contradiction, since its failure would give a chain A1⊂⋯⊂AqA_1\subset\cdots\subset A_q with more than [q/20]≥n[q/20]\ge\sqrt n steps outside XX, ending in Aq∗>nA_q^*>n (p. 229). Not reconstructed here.

Dependencies

None outside the paper.

Bears on

  • Problem 540: the statement for G=Z/NZG=\mathbb Z/N\mathbb Z is the problem's question with an unspecified constant; the site's "proved ... for all NN by Szemerédi [Sz70] (in fact for arbitrary finite abelian groups)". The paper leaves the constant (22, or 2\sqrt2 as Erdős later speculated) and the non-abelian case open.