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Statement

arXiv v5, p. 42 (journal p. 471): "Proposition 6.1. For any n≥1n\ge1 and any a∈Sym([n])a\in\mathrm{Sym}([n]) it holds that ∣S(a)∣≥n3/2/42|S(a)|\ge n^{3/2}/4\sqrt2."

The paper introduces it as "the best lower bound we are aware of", obtained "by an argument in [Sol05] (also present in [BGS17]), a variant of which we sketch below" ([Sol05] Solymosi, On distinct consecutive differences, arXiv:math/0503069; [BGS17] Balog, Granville and Solymosi, Gaps between fractional parts, and additive combinatorics). Section 6.2 records that essentially the best available upper bound for the minimum is the identity permutation's ∣S(idn)∣=n2−o(1)|S(\mathrm{id}_n)|=n^{2-o(1)}, extended in Example 6.2 to permutations of "bounded complexity"; Section 6.3 (p. 44; journal p. 474) asks Question 3: "Is it true that min⁡a∈Sym([n])∣S(n)∣\min_{a\in\mathrm{Sym}([n])}|S(n)| [sic] =n2−o(1)=n^{2-o(1)}? That is, is it true that for any δ>0\delta>0 there exists cδ>0c_\delta>0 such that for any n≥1n\ge1 the bound ∣S(a)∣≥cδn2−δ|S(a)|\ge c_\delta n^{2-\delta} holds for all a∈Sym([n])a\in\mathrm{Sym}([n])?" (the print's "∣S(n)∣|S(n)|" is ∣S(a)∣|S(a)|), and Question 4: "Does there exist an absolute constant c>0c>0 such that for any n≥1n\ge1 the bound ∣S(a)∣≥c∣S(idn)∣|S(a)|\ge c|S(\mathrm{id}_n)| holds for all a∈Sym([n])a\in\mathrm{Sym}([n])?", noting that "It is not the case that ∣S(a)∣|S(a)| is minimised for the trivial permutation idn\mathrm{id}_n, but none of the examples known to the author are significantly worse."

Source. Jakub Konieczny, On consecutive sums in permutations, arXiv:1504.07156v5 (27 August 2021), pp. 42--44; J. Combinatorics 12 (2021), no. 3, 413--477, pp. 471--474. The wording is identical in both editions. Library home: konieczny_2015_consecutive_sums_permutations.

Read depth. Claims checked: the proposition and Questions 3--4 were read clause by clause in the text layer of the arXiv v5 and on the journal pages; the one-page proof was read for structure and not checked; nothing here is independently reviewed.

Proof pointer

Page 42. Split S(a)S(a) into the sets Sk(a)S^k(a) of sums in (kn,(k+1)n](kn,(k+1)n]. For 1≤k≤(n+1)/41\le k\le(n+1)/4 and each uu, one of ∑i=unai\sum_{i=u}^na_i, ∑i=1uai\sum_{i=1}^ua_i exceeds knkn, and the least vv with ∑i=uv−1ai>kn\sum_{i=u}^{v-1}a_i>kn puts one sum in Sk(a)S^k(a) and a neighbor in Sk(a)∪Sk−1(a)S^k(a)\cup S^{k-1}(a); since ∣(R−R)∩N∣≤∣R∣2/2|(R-R)\cap\mathbb N|\le|R|^2/2 for R⊂NR\subset\mathbb N, this gives ∣Sk(a)∣+∣Sk−1(a)∣≥2n|S^k(a)|+|S^{k-1}(a)|\ge\sqrt{2n} (display (134)), and summing over k≤(n+1)/4k\le(n+1)/4 with ∣S0(a)∣=n|S^0(a)|=n yields ∣S(a)∣≥n2+12⌊n+14⌋2n≥n3/2/(42)|S(a)|\ge\frac n2+\frac12\lfloor\frac{n+1}4\rfloor\sqrt{2n}\ge n^{3/2}/(4\sqrt2).

Dependencies

The elementary difference-set inequality above; the argument follows Solymosi's.

Bears on

  • Problem 34: the site's g(n)=min⁡πS(π)≫n3/2g(n)=\min_\pi S(\pi)\gg n^{3/2} and its two expectations, "it may be true that g(n)≥n2−o(1)g(n)\ge n^{2-o(1)}, or even g(n)≫S(ι)g(n)\gg S(\iota)", are Questions 3 and 4; the problem page records an unreviewed 2026 proof claim on the site's tab that asserts a construction with g(n)=O(nlog⁡635)g(n)=O(n^{\log_635}) along a sequence.