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Statement

Theorem 4.5 (p. 151). Some function ε(n)=O(n1/3ln⁡n)\varepsilon(n)=O(n^{1/3}\ln n) has the following property. Let GG be a finite abelian group of order nn and let S⊂GS\subset G. Then

∣S∣>2n+ε(n)implies0∈Σ∗(S),|S|>\sqrt{2n}+\varepsilon(n)\quad\text{implies}\quad0\in\Sigma^*(S),

where Σ∗(S)\Sigma^*(S) is the set of sums of nonempty subsets of SS.

Source. Y. O. Hamidoune and G. Zémor, On zero-free subset sums, Acta Arith. 78 (1996), no. 2, 143--152, DOI 10.4064/aa-78-2-143-152; Theorem 4.5 on printed p. 151 (PDF p. 9), read on the page image and in the text layer. The inequality is printed strict (>>), although the introduction (p. 143) states the result with ≥\ge.

Read depth. Claims checked: the statement was read clause by clause. The proof (Section 4, pp. 148--151) was read for structure only.

Proof pointer

Section 4 adapts the prime-order argument: Lemma 4.1 extracts from SS a subset KK with K∩(−K)=∅K\cap(-K)=\emptyset and bounds κ(S∪(−S))\kappa(S\cup(-S)); Lemma 4.3 and Corollary 4.4 give ∣Σ∗(T)∣≥min⁡(n,12k(k+1)−3(k+1)3/2−3dk(1+ln⁡k))|\Sigma^*(T)|\ge\min(n,\tfrac12k(k+1)-3(k+1)^{3/2}-3dk(1+\ln k)) (display (13)) for a subset TT of SS under a hypothesis on the subgroups generated by large subsets of SS, which Theorem 2.5 supplies when ∣S∣>3n/d+k+2dlog⁡3/2n|S|>3\sqrt{n/d}+k+2d\log_{3/2}n (display (14)); choosing d∼n1/3d\sim n^{1/3} gives the theorem.

Dependencies

Kneser's and Scherk's theorems, Olson's Theorem 2.5 and the paper's Section 4 lemmas.

Bears on

  • Problem 540: the best general bound in hand, the site's "Hamidoune and Zémor proved the bound (1+o(1))2N(1+o(1))\sqrt{2N} for arbitrary abelian groups of order NN"; it sharpens Szemerédi's unspecified constant to 2\sqrt2 up to a lower-order term.