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Statement

Section 6 (p. 56): "It is very probable that the estimation (1.5) approaches the best possible also for j>2j>2. More exactly, an inequality of the form

(6.1)kj(n)>cn(2j−1)/j\text{(6.1)}\qquad k_j(n)>cn^{(2j-1)/j}

probably holds also for j>2j>2 where cc depends only upon jj at most. A proof of this assertion would follow if it could be proved for all nn-values of the form n=pjn=p^j, pp prime. We should need the existence of a system BB of pjp^j combinations formed from elements 1,2,…,pj1,2,\ldots,p^j, taken pj−1p^{j-1} at a time, with the following property: no system (i1,i2,…,ij)(i_1,i_2,\ldots,i_j) with 1≤i1<i2<⋯<ij≤pj1\le i_1<i_2<\cdots<i_j\le p^j can occur in more than (j−1)(j-1) combinations of the system BB. For j=2j=2 thsi [sic] problem had been solved in Section 5." Section 2 (p. 51) adds: "It is very probable that also for j≥3j\ge3 lim⁡n→∞k(n)/n(2j−1)/j\lim_{n\to\infty}k(n)/n^{(2j-1)/j} exists", where the print's k(n)k(n) is kj(n)k_j(n).

Here kj(n)k_j(n) is the least number of 11's in an n×nn\times n 00--11 matrix that forces a j×jj\times j minor of 11's (p. 50); by (3.1) the graph number Hj(n)H_j(n) is at most 1+[kj∗(n)/2]1+[k_j^*(n)/2], so a lower bound for ex⁡(n;Kj,j)\operatorname{ex}(n;K_{j,j}) of order n2−1/jn^{2-1/j} is the graph-theoretic form of (6.1). Brown's paper of 1966 attributes the conjecture for j=3j=3 to this paper and to Erdős.

Source. Colloq. Math. 3 (1954), 50--57; Section 6 on printed p. 56 (PDF p. 4, left half) and the Section 2 remark on printed p. 51 (PDF p. 1, right half), read on the page images at 200 dpi of the retained two-up image-only scan identified in the source digest.

Read depth. Claims checked: both passages were read clause by clause on the page images. Nothing is proved.

Proof pointer

None: a conjecture with a proposed route. Section 5 (pp. 54--55) carries out the route for j=2j=2 with the p2p^2 combinations Jab={kp+⟨a+bk⟩+1:k=0,…,p−1}J_{ab}=\{kp+\langle a+bk\rangle+1:k=0,\ldots,p-1\}, any two of which share at most one element, giving a matrix with p3=n3/2p^3=n^{3/2} ones and no minor of order 22 of 11's, and hence (1.3).

Dependencies

None.

Bears on

  • Problem 714: the 1954 origin of the conjecture that n2−1/rn^{2-1/r} is the right order, in the matrix formulation; the graph question is the same by (3.1).