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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Inequality (2) (p. 221), stated with (1):

lim sup⁡kf(k)2−kk−2⩽log⁡2.(2)\limsup_kf(k)2^{-k}k^{-2}\leqslant\log2.\qquad(2)

Inequality (2.1) (p. 221), which the paper gives as the meaning of (2): for every ε>0\varepsilon>0 there is KεK_\varepsilon such that

f(k)⩽2kk2log⁡(2+ε)wheneverk>Kε.(2.1)f(k)\leqslant2^kk^2\log(2+\varepsilon)\quad\text{whenever}\quad k>K_\varepsilon.\qquad(2.1)

The logarithm is natural. The printed signs are the weak ⩽\leqslant; the scan's text layer renders that of (2) as a strict sign and that of (2.1) as the letter G.

Existence (p. 223). The same argument shows that f(k)f(k) exists for every kk, that is, some complete directed graph has property SkS_k; in the paper's words, "the existence of f(k)f(k) itself is a consequence of the contradiction implied by (3) for all sufficiently large nn". The paper adds that the probabilistic language is for intuition and that the proof could be recast as a purely combinatorial count.

Source. P. Erdős, On a problem in graph theory, Math. Gaz. 47 (1963), 220--223 (DOI 10.2307/3613396); printed pp. 221--223 = PDF pp. 2--4 of the archive scan, read on the page images. The edition read is identified in the source digest.

Read depth. Claims checked: displays (2) and (2.1) and the closing sentences of p. 223 were read clause by clause on the page images. The proof (§3, pp. 222--223) was read for structure only.

Proof pointer

§3, pp. 222--223: the (n2)\binom n2 joins of nn vertices are directed in 2n(n−1)/22^{n(n-1)/2} ways; for a fixed kk-set EE a vertex x∉Ex\notin E is efficient for EE with probability 2−k2^{-k}, so all n−kn-k other vertices are deficient with probability (1−2−k)n−k(1-2^{-k})^{n-k}, and the probability that some kk-set has no efficient vertex is at most pn=(nk)(1−2−k)n−kp_n=\binom nk(1-2^{-k})^{n-k}. If no graph has property SkS_k then pn≥1p_n\ge1, which with (nk)≤nk/k!\binom nk\le n^k/k! and 1−2−k<e−2−k1-2^{-k}<e^{-2^{-k}} gives (3) in the form 1/(k2k)<(log⁡n)/n1/(k2^k)<(\log n)/n, impossible for n>2kk2log⁡(2+ε)n>2^kk^2\log(2+\varepsilon) and kk large. Not checked here.

Dependencies

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Bears on

  • Problem 902: inequalities (2) and (2.1) are the upper bound the site quotes as f(n)≪n22nf(n)\ll n^22^n (the site's nn is the paper's kk), here with the explicit constant log⁡(2+ε)\log(2+\varepsilon) for k>Kεk>K_\varepsilon; the proof also gives the existence of the problem's function for every kk (p. 223).