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Source. Proposition 1, p. 4, of Patrick Letendre, Divisors of an Integer in a Short Interval, arXiv preprint arXiv:2503.12146v1 (15 March 2025), the version named on the source card.

Statement

Setting (p. 1). Dn(X,Y)D_n(X,Y) is the number of divisors dd of nn with X≤d≤X+YX\le d\le X+Y.

Proposition 1 (p. 4, quoted). "Let n≥1n\ge1 be a fixed integer, and let 0<θ<10<\theta<1 and 0<ϵ<θ20<\epsilon<\theta^2 be fixed real numbers. Then

Dn(nθ,nθ2−ϵ)≪θ(1−θ)ϵ+1θ(1−θ)."D_n(n^\theta,n^{\theta^2-\epsilon})\ll\frac{\theta(1-\theta)}{\epsilon}+\frac{1}{\theta(1-\theta)}."

The right side does not involve nn. The printed statement fixes nn and does not name the dependence of the implied constant. The proof (p. 4) ends with the alternative k≤4/(θ(1−θ))k\le4/(\theta(1-\theta)) or k≤3 θ(1−θ)/ϵk\le3\,\theta(1-\theta)/\epsilon for the number k≥2k\ge2 of divisors in the window, with no dependence on nn, so the bound holds uniformly in nn (a reading of the proof by this page).

The paper states it in Section 4 as one of three statements used for Theorem 1. On p. 2 it refers to Proposition 1 when it says that a relaxed version of Conjecture 2 would ask for a larger region in which ξ(θ,η)=1\xi(\theta,\eta)=1; in Theorem 1's notation the proposition covers windows of length nηn^\eta with η<θ2\eta<\theta^2, inside the region η≤θ2\eta\le\theta^2 where ξ(θ,η)=1\xi(\theta,\eta)=1.

Read depth. Claims checked: the statement was read clause by clause on the printed page, and the short proof was read. Not independently reviewed.

Proof pointer

Page 4. Take divisors d1,…,dkd_1,\ldots,d_k of nn in the window. Their least common multiple is at most nn, each pairwise greatest common divisor is at most the gap ∣di−dj∣≤nθ2−ϵ\lvert d_i-d_j\rvert\le n^{\theta^2-\epsilon}, and each di≥nθd_i\ge n^\theta. Lemma 1 (p. 2) with t=θk+ζt=\theta k+\zeta, 0≤ζ<10\le\zeta<1, then gives, on comparing exponents of nn, ϵk(k−1)≤(θ−θ2)k+ζ(ζ+1)\epsilon k(k-1)\le(\theta-\theta^2)k+\zeta(\zeta+1), which forces one of the two bounds on kk above.

Dependencies

Lemma 1 (p. 2): for positive integers d1,…,dkd_1,\ldots,d_k and every integer tt, [d1,…,dk]t(t+1)/2∏1≤i<j≤k(di,dj)≥∏1≤i≤kdit[d_1,\ldots,d_k]^{t(t+1)/2}\prod_{1\le i<j\le k}(d_i,d_j)\ge\prod_{1\le i\le k}d_i^t, where [⋅][\cdot] is the least common multiple and (⋅,⋅)(\cdot,\cdot) the greatest common divisor. The paper takes it from H. Cohen, Diviseurs appartenant à une même classe résiduelle, Seminar on number theory 1982-83, Université de Bordeaux I, Exp. No. 16, Corollaire 1.4.

Bears on

  • Problem 886: at θ=1/2\theta=1/2 the proposition gives, for each fixed 0<δ<1/40<\delta<1/4, at most O(1/δ)O(1/\delta) divisors of nn in [n1/2,n1/2+n1/4−δ][n^{1/2},n^{1/2}+n^{1/4-\delta}], for every nn. This answers the problem's question for each ϵ=1/4+δ\epsilon=1/4+\delta with 1/4<ϵ<1/21/4<\epsilon<1/2; for ϵ≥1/2\epsilon\ge1/2 the window has length at most 11. The problem page records that Erdős and Rosenfeld's bound already answers the question for every ϵ≥1/4\epsilon\ge1/4. The range 0<ϵ≤1/40<\epsilon\le1/4 would need windows of length nηn^\eta with η≥θ2\eta\ge\theta^2, outside the proposition's hypothesis.
  • Problem 887: the problem's windows have length Cn1/4Cn^{1/4}, longer than the n1/4−δn^{1/4-\delta} the proposition allows at θ=1/2\theta=1/2, so it settles no instance.
  • Problem 873: the paper does not mention this problem. A note posted in the problem's thread (claim page) combines this proposition with packing lemmas of its own in an argument that it says answers the question for every exponent above 1/41/4; that reduction is the note's, not the paper's, and is not checked here.