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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (p. 9). A primitive sequence is a sequence of integers 0<a1<a2<⋯0<a_1<a_2<\cdots in which no term divides any other, and for such a sequence AA

fA(x)=∑ai<x1ai.f_A(x)=\sum_{a_i<x}\frac1{a_i}.

Throughout the paper c1,c2,…c_1,c_2,\ldots are suitable positive absolute constants. The paper recalls Behrend's theorem, its display (1): every primitive sequence satisfies fA(x)<c1log⁡x/(log⁡log⁡x)1/2f_A(x)<c_1\log x/(\log\log x)^{1/2}. It also recalls Pillai's observation, its display (2): for every xx there is a primitive sequence a1<⋯<ak≤xa_1<\cdots<a_k\le x with fA(x)>c2log⁡x/(log⁡log⁡x)1/2f_A(x)>c_2\log x/(\log\log x)^{1/2}, so (1) is best possible for finite sequences.

Theorem 1 (p. 9, quoted). "Let AA be an infinite primitive sequence. Then"

fA(x)=o(log⁡x/(log⁡log⁡x)1/2).(3)f_A(x)=o\bigl(\log x/(\log\log x)^{1/2}\bigr).\qquad(3)

The paper reads this as saying that Behrend's bound, though best possible for finite primitive sequences, can be improved for infinite ones.

Sharpness, display (4) (p. 9, proof outlined only). If h(x)→∞h(x)\to\infty arbitrarily slowly, there is a primitive sequence AA with

lim sup⁡x→∞fA(x) h(x) (log⁡log⁡x)1/2/log⁡x=∞.\limsup_{x\to\infty}f_A(x)\,h(x)\,(\log\log x)^{1/2}/\log x=\infty.

The print sets the exponent 12\tfrac12 on the xx inside the double logarithm, as (log⁡log⁡x1/2)(\log\log x^{1/2}); the display is read here with the exponent on log⁡log⁡x\log\log x, as in (1) to (3), which is the reading under which it shows that Theorem 1 is best possible, as the paper says it does. The outline: take x1<x2<⋯x_1<x_2<\cdots tending to infinity fast enough, and let AA consist, in each interval (xν−1,xν)(x_{\nu-1},x_\nu), of the integers with exactly [log⁡log⁡xν][\log\log x_\nu] distinct prime factors, all greater than xν−1x_{\nu-1} (and no prime factor at most xν−1x_{\nu-1}). The paper states that a computation by the methods of Erdős's 1948 paper on integers with exactly kk prime factors gives (4) once xν→∞x_\nu\to\infty fast enough in terms of hh, and leaves the details to the reader.

Source. P. Erdős, A. Sárközy and E. Szemerédi, On a theorem of Behrend, J. Austral. Math. Soc. 7 (1967), 9--16: the setting, Theorem 1 and (4) on p. 9, the proof on pp. 10--14. The edition read is identified on the source card.

Read depth. Claims checked: the setting, Theorem 1, display (4) and its outline were read clause by clause on the printed page. The proof was read but not checked step by step. Nothing here is independently reviewed.

Proof pointer

Pp. 10--14, by contradiction. Squarefree reduction (p. 10): split AA by the largest square k2k^2 dividing its terms; by (1) and the convergence of ∑1/k2\sum1/k^2, a sequence violating (3) has a part, for one fixed k0k_0, that violates (3), and dividing its terms by k02k_0^2 gives a primitive sequence of squarefree integers violating (3). For such a sequence there are x1<x2<⋯x_1<x_2<\cdots growing fast with ∑xν−1<ai<xν1/ai>c3log⁡xν/(log⁡log⁡xν)1/2\sum_{x_{\nu-1}<a_i<x_\nu}1/a_i>c_3\log x_\nu/(\log\log x_\nu)^{1/2} (the paper's (5)).

Lemma 1 (p. 10), called crucial there: let u<w≤yu<w\le y with ww sufficiently large compared to uu, and let u<a1<⋯<ak<wu<a_1<\cdots<a_k<w be squarefree with no aia_i dividing another and ∑i≤k1/ai>c3log⁡w/(log⁡log⁡w)1/2\sum_{i\le k}1/a_i>c_3\log w/(\log\log w)^{1/2}. Then the integers b≤yb\le y of the form aiQa_iQ, with Q≤y/aiQ\le y/a_i and every prime factor of QQ greater than uu, satisfy ∑1/b>c4log⁡y\sum1/b>c_4\log y, where c4c_4 depends only on c3c_3.

From Lemma 1 to Theorem 1 (pp. 10--11): with λc4>2\lambda c_4>2 and y=xλy=x_\lambda, apply Lemma 1 to each block (xν−1,xν)(x_{\nu-1},x_\nu), 1≤ν≤λ1\le\nu\le\lambda. Primitivity and the condition on prime factors make the λ\lambda sets of integers b<yb<y disjoint, so the reciprocals of the integers below yy sum to more than λc4log⁡y>2log⁡y\lambda c_4\log y>2\log y, which is impossible.

Proof of Lemma 1 (pp. 11--14): for y=wy=w it reduces to a lower bound on divisor counts, ∑n≤wd2(n)>c5wlog⁡w\sum_{n\le w}d_2(n)>c_5w\log w with d2(n)d_2(n) the number of the bb's dividing nn, obtained from Lemma 2, a combinatorial statement on families of subsets proved through Lemma 3 and Sperner's theorem; the general case y>wy>w follows from the case y=wy=w and a bound of de Bruijn on integers free of prime factors up to ww (p. 14).

Dependencies

Behrend's theorem, F. Behrend, On sequences of numbers not divisible one by another, J. London Math. Soc. 10 (1935), 42--45; E. Sperner, Ein Satz über Untermengen einer endlichen Menge, Math. Z. 27 (1928), 544--548; and N. G. de Bruijn, On the number of uncancelled elements in the sieve of Eratosthenes, Indag. Math. 12 (1950), 247--256.

Bears on

  • Problem 143: the problem asks whether a countably infinite A⊂(1,∞)A\subset(1,\infty) with ∣kx−y∣≥1\lvert kx-y\rvert\ge1 for all distinct x,y∈Ax,y\in A and integers k≥1k\ge1 must satisfy, among other senses of sparseness, ∑x<n, x∈A1/x=o(log⁡n)\sum_{x<n,\,x\in A}1/x=o(\log n). For a set of integers the hypothesis says exactly that no element divides another, and for such an infinite set Theorem 1 gives the sum as o(log⁡n/(log⁡log⁡n)1/2)o(\log n/(\log\log n)^{1/2}), already o(log⁡n)o(\log n) by Behrend's bound (1). The theorem says nothing about sets of non-integers.
  • Problem 892: the problem asks for a condition on b1<b2<⋯b_1<b_2<\cdots equivalent to the existence of a primitive sequence with an≪bna_n\ll b_n. If an≤Cbna_n\le Cb_n for all nn, then ∑bn<x1/bn≤C fA(Cx)\sum_{b_n<x}1/b_n\le C\,f_A(Cx), so by Theorem 1 every such bb-sequence has ∑bn<x1/bn=o(log⁡x/(log⁡log⁡x)1/2)\sum_{b_n<x}1/b_n=o(\log x/(\log\log x)^{1/2}) (an observation of this page, not of the paper). This is a necessary condition only; the paper does not address the problem's question.