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Source. Problem 22 and Theorem 6.1, p. 11 (Section 6, "Subsets with no repeated distances", pp. 10--13), with Table 2 (p. 11) and the proof of Theorem 6.1 on pp. 11--12, of Adam Sheffer, Distinct Distances: Open Problems and Current Bounds, arXiv:1406.1949v3 (2 July 2018), the edition read for the source card.

Statement

Notation (p. 11). For a set P⊂R2\mathcal P\subset\mathbb R^2, subset(P)\mathsf{subset}(\mathcal P) is the size of the largest P′⊂P\mathcal P'\subset\mathcal P in which every distance is spanned at most once: there are no a,b,c,d∈P′a,b,c,d\in\mathcal P' with ∣ab∣=∣cd∣>0|ab|=|cd|>0, the case a=ca=c included. subset(n)=min⁡∣P∣=nsubset(P)\mathsf{subset}(n)=\min_{|\mathcal P|=n}\mathsf{subset}(\mathcal P), the largest number such that every set of nn points in R2\mathbb R^2 contains a subset of that size spanning no distance more than once.

Problem 22 (p. 11), credited to Erdős. "Find the asymptotic value of subset(n)\mathsf{subset}(n)." (quoted)

Theorem 6.1 (p. 11), credited to Charalambides. Quoted: "subset(n)=Ω(n1/3/log⁡1/3n)\mathsf{subset}(n)=\Omega(n^{1/3}/\log^{1/3}n)."

Upper bound (p. 11): a subset spanning no distance twice has (∣P′∣2)≤D(P)\binom{|\mathcal P'|}{2}\le D(\mathcal P), so the n×n\sqrt n\times\sqrt n section L\mathcal L of Z2\mathbb Z^2, with D(L)=Θ(n/log⁡n)D(\mathcal L)=\Theta(n/\sqrt{\log n}), gives subset(n)≤subset(L)=O(n/(log⁡n)1/4)\mathsf{subset}(n)\le\mathsf{subset}(\mathcal L)=O(\sqrt n/(\log n)^{1/4}). Earlier lower bounds the survey records: Ω(n0.25)\Omega(n^{0.25}) (Lefmann and Thiele) and Ω(n0.288)\Omega(n^{0.288}) (Dumitrescu).

Proof pointer

Pp. 11--12, the survey's own proof of Theorem 6.1. It uses two cited counts: Guth and Katz's O(n3log⁡n)O(n^3\log n) bound on quadruples of distinct points (a,b,c,d)(a,b,c,d) with ∣ab∣=∣cd∣>0|ab|=|cd|>0, and Pach and Tardos's O(n2.137)O(n^{2.137}) bound on isosceles and equilateral triangles. Keep each point with probability p=1/(2αn2log⁡n)1/3p=1/(2\alpha n^2\log n)^{1/3} and delete one point from each surviving quadruple and triangle; the expected number of points left is of order n1/3/(log⁡n)1/3n^{1/3}/(\log n)^{1/3}, and what is left spans no distance twice.

Read depth

Claims checked: the definition, Problem 22, Theorem 6.1 and the recorded bounds were read clause by clause on the print, and the proof was followed. The two counts it cites and the earlier bounds were not checked against their sources here.

Bears on

  • Problem 1208: for d=2d=2 the problem's F2(n)F_2(n), read as the largest size such that every nn points contain that many points with all distances distinct, is subset(n)\mathsf{subset}(n), and the problem asks for its estimate. The survey records $\Omega(n^{1/3}/\log^{1/3}n)\le\mathsf{subset}(n)\le O(\sqrt n/(\log n)^{1/4})$ and leaves the asymptotic value open as Problem 22. The case d≥3d\ge3 is on the Problem 25 page.