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Source. Larry Guth and Nets Hawk Katz, On the Erdős distinct distances problem in the plane, Annals of Mathematics 181 (2015), 155--190, DOI 10.4007/annals.2015.181.1.2 (source card). The definition of Q(P)Q(P) is on p. 159, Proposition 2.2 on p. 160, and its proof is assembled on pp. 161 and 166. In arXiv v3 (arXiv:1011.4105v3) the same statement, with the same label, is on p. 5.

Read depth. Claims checked: the definition of distance quadruples, the statement, and the counting identity in the proof of Lemma 2.1 were read clause by clause on the printed pages and compared with arXiv v3. The proof was read for structure only and is not independently reviewed here.

Statement

For a set P⊂R2P\subset\mathbb R^2, Q(P)Q(P) is the set of quadruples (p1,p2,p3,p4)∈P4(p_1,p_2,p_3,p_4)\in P^4 with d(p1,p2)=d(p3,p4)≠0d(p_1,p_2)=d(p_3,p_4)\ne0, the distance quadruples (p. 159, equation (2.1)).

Proposition 2.2 (p. 160). "For any set P⊂R2P\subset\mathbf R^2 of NN points, the number of quadruples in Q(P)Q(P) is bounded by ∣Q(P)∣≲N3log⁡N|Q(P)|\lesssim N^3\log N."

The paper defines A≳BA\gtrsim B as A>CBA>CB for a universal constant C>0C>0 (p. 155), and A≲BA\lesssim B is read the same way, as A<CBA<CB. In the proof of Lemma 2.1 (p. 160), if nin_i is the number of ordered pairs (p,q)(p,q) of distinct points of PP at the ii-th distance did_i, then ∣Q(P)∣=∑ini2|Q(P)|=\sum_i n_i^2. The paper notes that the bound is sharp up to constant factors when PP is a square grid (p. 160; appendix, pp. 185--187).

Proof pointer

By Lemma 2.4 (p. 160) and equation (2.2) (p. 161), ∣Q(P)∣=∑k=2N(2k−2)∣Gk(P)∣|Q(P)|=\sum_{k=2}^N(2k-2)|G_k(P)|, where Gk(P)G_k(P) is the set of orientation-preserving rigid motions gg with ∣P∩gP∣≥k|P\cap gP|\ge k. Proposition 2.5 (p. 161) bounds ∣Gk(P)∣≲N3k−2|G_k(P)|\lesssim N^3k^{-2} for 2≤k≤N2\le k\le N, and summing gives N3log⁡NN^3\log N. Proposition 2.5 combines Lemma 2.12 (p. 165) for translations with Theorems 2.10 and 2.11 for the other motions, the two cases of Theorem 1.2 (summary on p. 166). With Lemma 2.1 the proposition gives Theorem 1.1.

Bears on. Problem 95: if f(ui)f(u_i) counts the unordered pairs at distance uiu_i, then ni=2f(ui)n_i=2f(u_i), so the proposition gives ∑if(ui)2≪n3log⁡n\sum_i f(u_i)^2\ll n^3\log n, which implies the problem's bound ≪ϵn3+ϵ\ll_\epsilon n^{3+\epsilon} for every ϵ>0\epsilon>0. The problem's [[../wiki/problems/distance_problems/E0095/claims/2010_11_17_guth_katz|claim page]] records this deduction; the problem's standing is derived there, not here.