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Source. Proposition 1, p. 66, with the discussion of Section 6, pp. 92--93, of Peter Fishburn, "Convex polygons with few intervertex distances," Computational Geometry 5 (1995), no. 2, 65--93, doi:10.1016/0925-7721(94)00020-v, the edition named on the source card.

Read depth. Claims checked: the statement, the values and the conjecture of p. 66, and Section 6 (pp. 92--93) were read clause by clause on the page images. Nothing here is independently reviewed.

Statement

Proposition 1 (p. 66, quoted). "For every n⩾7n\geqslant7 there is a largest nonnegative integer f(n)f(n) such that every convex nn-gon with no more than ⌊n/2⌋+f(n)\lfloor n/2\rfloor+f(n) intervertex distances has all nn vertices on a circle, and these vertices are among those of some regular polygon."

The paper presents it (p. 65) as a consequence of its results for even nn together with Altman's theorem: for odd nn the minimum is attained only by RnR_n (Theorem 1), and for even n≥8n\ge8 only by RnR_n and Rn+1−1R_{n+1}-1 (Theorem 2), so f(n)≥0f(n)\ge0. Section 6 (p. 92) restates the conclusion as: the polygon is a regular (n+k)(n+k)-gon with k≥0k\ge0 vertices removed.

Values (p. 66 and Section 6, pp. 92--93). f(7)=1f(7)=1, by the classification of M7(4)M_7(4) in Theorem 3, and f(8)=f(10)=0f(8)=f(10)=0. If M9(5)M_9(5) consists of R10−1R_{10}-1 and versions of R11−2R_{11}-2, then f(9)=1f(9)=1; an added-in-proof note (p. 93) states that this description of M9(5)M_9(5) is verified in a separate paper of Erdős and Fishburn.

Upper bounds (Section 6, pp. 92--93). Interweaving the vertices of two concentric copies of RNR_N of different diameters gives a convex 2N2N-gon A2NA_{2N}, generalizing A6A_6, with m(A2N)=3N/2−1m(A_{2N})=3N/2-1 for even NN and 3(N−1)/23(N-1)/2 for odd NN. Hence

f(2N)≤N/2−2  (N≥4 even),f(2N)≤(N−5)/2  (N≥5 odd),f(2N)\le N/2-2\ \ (N\ge4\text{ even}),\qquad f(2N)\le(N-5)/2\ \ (N\ge5\text{ odd}),

and deleting a vertex of A2NA_{2N} gives

f(2N−1)≤N/2−1  (N≥4 even),f(2N−1)≤(N−3)/2  (N≥5 odd).f(2N-1)\le N/2-1\ \ (N\ge4\text{ even}),\qquad f(2N-1)\le(N-3)/2\ \ (N\ge5\text{ odd}).

The paper lists the consequences f(12)≤1f(12)\le1, f(14)≤1f(14)\le1, f(7)≤1f(7)\le1, f(9)≤1f(9)\le1, f(11)≤2f(11)\le2 and f(13)≤2f(13)\le2. On the page image the minus signs of the first display for f(2N−1)f(2N-1) are not printed; they are read from the listed consequences, which they match.

Open (pp. 66, 92). The paper conjectures that ff is unbounded and names the determination of f(n)f(n) for all n≥9n\ge9 as a main open problem.

Proof pointer

The existence of f(n)f(n) is drawn from Theorems 1 and 2 as above; the paper writes no separate proof. The values and bounds are argued in Section 6 (pp. 92--93) from the classifications and the polygons A2NA_{2N}.

Dependencies

Theorem 1, Theorem 2, Theorem 3.

Bears on

  • Problem 132: in a set of vertices of a regular polygon every distance occurs at most nn times among nn of them, so a convex nn-gon with at most ⌊n/2⌋+f(n)\lfloor n/2\rfloor+f(n) distances has all its distances occurring at most nn times (an observation made here). Growth of ff would therefore bear on the second question in convex position, but the paper only conjectures that ff is unbounded and proves upper bounds.