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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Theorem 3 (p. 250, quoted). "Let the maximum and minimum distances determined by nn points in a plane be denoted by rr and r′r', respectively. Then rr can occur at most nn times and r′r' at most 3n−63n-6 times."

The bound for rr is the one the paper calls well known in Section 4 (p. 249), citing Jahresbericht der Deutschen Math. Vereinigung 43 (1934), p. 114. The bound 3n−63n-6 comes from Euler's formula for planar graphs, which gives it for n≥3n\ge3 (an observation of this page; the paper states no range).

Remarks after the theorem (p. 250).

  • The paper says it is easy to give nn points at which the maximum distance occurs exactly nn times.
  • It says that more complicated arguments, not given, prove that r′r' occurs at most 3n−cn1/23n-cn^{1/2} times with cc a constant, and that the triangular lattice shows r′r' can occur 3n−c1n1/23n-c_1n^{1/2} times; it did not determine exactly how often r′r' can occur.

Higher dimensions (p. 250, before and after the theorem).

  • The paper reports, from oral communication, Vázsonyi's conjecture that in three-dimensional space the maximum distance cannot occur more than 2n−22n-2 times.
  • It observes that a bound of knkn on the occurrences of the maximum distance in kk-dimensional space would establish Borsuk's conjecture, stated as "Each kk-dimensional subset of diameter 1 can be decomposed into k+1k+1 summands each having diameter <1<1."
  • It says that generalizing Theorem 3 to three dimensions already presents great difficulties, and that it would be of some interest to determine the largest number of points on the kk-dimensional unit sphere with any two at distance ≥1\ge1.

Source. P. Erdős, On sets of distances of nn points, Amer. Math. Monthly 53 (1946), 248--250; Section 4 runs from p. 249 to p. 250, with Theorem 3 and the remarks on p. 250. The copy read is identified on the source card.

Read depth. Claims checked: the statement, the remarks and the proof were read clause by clause on the page images. Nothing here is independently reviewed.

Proof pointer

Pp. 249--250. Maximum distance. Any two segments of length rr joining the points must meet, since otherwise the four endpoints would have diameter greater than rr. Join two points when their distance is rr. If every point has at most two such neighbours, there are at most nn pairs. If a point P1P_1 has three, P2,P3,P4P_2,P_3,P_4 with P1P3P_1P_3 between P1P2P_1P_2 and P1P4P_1P_4, then P3P_3 has no other neighbour, since a further segment from P3P_3 would have to cross both P1P2P_1P_2 and P1P4P_1P_4; removing P3P_3 lowers both counts by one, and induction finishes. Minimum distance. Each point has at most six points at distance r′r', which already gives 3n3n. Two segments of length r′r' cannot cross, as that would produce two points closer than r′r', so the graph of minimum-distance pairs is planar and Euler's formula gives at most 3n−63n-6 edges.

Dependencies

The bound for the maximum distance in the plane, cited by the paper to Jahresbericht der Deutschen Math. Vereinigung 43 (1934), p. 114; Euler's formula for planar graphs.

Bears on

  • Problem 223: for d=2d=2 the theorem gives f2(n)≤nf_2(n)\le n, and the paper remarks that nn occurrences are easy to attain; the paper attributes the bound to the 1934 Jahresbericht note rather than claiming it. For d=3d=3 the paper records Vázsonyi's conjecture 2n−22n-2 without proof, and it links a knkn bound in kk dimensions to Borsuk's conjecture.
  • Problem 132: the diameter is always one occurring distance that occurs between at most nn pairs; the problem asks for a second such distance and for their number to tend to infinity, which the paper does not address.
  • Problem 1084: for d=2d=2 and n≥3n\ge3, nn points pairwise at distance at least 11 have at most 3n−63n-6 pairs at distance exactly 11 by the bound for r′r' (when the minimum distance exceeds 11 there are none). The remarks after the theorem sharpen this, without proof, to 3n−cn1/23n-cn^{1/2} and give the triangular lattice with 3n−c1n1/23n-c_1n^{1/2} such pairs.