Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Theorem 3 (p. 250, quoted). "Let the maximum and minimum distances determined by points in a plane be denoted by and , respectively. Then can occur at most times and at most times."
The bound for is the one the paper calls well known in Section 4 (p. 249), citing Jahresbericht der Deutschen Math. Vereinigung 43 (1934), p. 114. The bound comes from Euler's formula for planar graphs, which gives it for (an observation of this page; the paper states no range).
Remarks after the theorem (p. 250).
- The paper says it is easy to give points at which the maximum distance occurs exactly times.
- It says that more complicated arguments, not given, prove that occurs at most times with a constant, and that the triangular lattice shows can occur times; it did not determine exactly how often can occur.
Higher dimensions (p. 250, before and after the theorem).
- The paper reports, from oral communication, Vázsonyi's conjecture that in three-dimensional space the maximum distance cannot occur more than times.
- It observes that a bound of on the occurrences of the maximum distance in -dimensional space would establish Borsuk's conjecture, stated as "Each -dimensional subset of diameter 1 can be decomposed into summands each having diameter ."
- It says that generalizing Theorem 3 to three dimensions already presents great difficulties, and that it would be of some interest to determine the largest number of points on the -dimensional unit sphere with any two at distance .
Source. P. Erdős, On sets of distances of points, Amer. Math. Monthly 53 (1946), 248--250; Section 4 runs from p. 249 to p. 250, with Theorem 3 and the remarks on p. 250. The copy read is identified on the source card.
Read depth. Claims checked: the statement, the remarks and the proof were read clause by clause on the page images. Nothing here is independently reviewed.
Proof pointer
Pp. 249--250. Maximum distance. Any two segments of length joining the points must meet, since otherwise the four endpoints would have diameter greater than . Join two points when their distance is . If every point has at most two such neighbours, there are at most pairs. If a point has three, with between and , then has no other neighbour, since a further segment from would have to cross both and ; removing lowers both counts by one, and induction finishes. Minimum distance. Each point has at most six points at distance , which already gives . Two segments of length cannot cross, as that would produce two points closer than , so the graph of minimum-distance pairs is planar and Euler's formula gives at most edges.
Dependencies
The bound for the maximum distance in the plane, cited by the paper to Jahresbericht der Deutschen Math. Vereinigung 43 (1934), p. 114; Euler's formula for planar graphs.
Bears on
- Problem 223: for the theorem gives , and the paper remarks that occurrences are easy to attain; the paper attributes the bound to the 1934 Jahresbericht note rather than claiming it. For the paper records Vázsonyi's conjecture without proof, and it links a bound in dimensions to Borsuk's conjecture.
- Problem 132: the diameter is always one occurring distance that occurs between at most pairs; the problem asks for a second such distance and for their number to tend to infinity, which the paper does not address.
- Problem 1084: for and , points pairwise at distance at least have at most pairs at distance exactly by the bound for (when the minimum distance exceeds there are none). The remarks after the theorem sharpen this, without proof, to and give the triangular lattice with such pairs.