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Statement

Setting (p. 248, Section 3). g(n;r)g(n;r) is the maximum number of times a given distance rr can occur among nn points of a plane, that is, the largest number of pairs at distance rr. The proof and the closing remark write it g(n)g(n).

Theorem 2 (p. 249, quoted).

n1+c/log⁡log⁡n<g(n;r)<n3/2.n^{1+c/\log\log n}<g(n;r)<n^{3/2}.

The constant cc is not specified. The proof of the upper bound uses the inequality (2), which the paper derives for n≥4n\ge4.

Remark (p. 249, after the proof). The paper says it seems likely that g(n)<n1+εg(n)<n^{1+\varepsilon}; it states this as a likelihood, neither proved nor labelled a conjecture, and does not spell out the quantifier on ε\varepsilon.

Source. P. Erdős, On sets of distances of nn points, Amer. Math. Monthly 53 (1946), 248--250; the definition on p. 248, Theorem 2, its proof and the remark on p. 249. The copy read is identified on the source card.

Read depth. Claims checked: the definition, the statement and the remark were read clause by clause on the page images, and the proof of the upper bound was followed. The lower-bound construction is only sketched in the paper and was not re-derived. Nothing here is independently reviewed.

Proof pointer

P. 249. Upper bound. Let xix_i be the number of points at distance rr from PiP_i, ordered so that x1≥x2≥⋯≥xnx_1\ge x_2\ge\cdots\ge x_n; then g(n;r)=max⁡12∑xig(n;r)=\max\frac12\sum x_i. Two circles of radius rr about different centres share at most two points, which gives the paper's inequality (1), ∑i≤j(xi−2i+2)≤n\sum_{i\le j}(x_i-2i+2)\le n for each jj. Taking a=[n1/2]a=[n^{1/2}], the first aa of the xix_i sum to less than 2n−2ϵn1/22n-2\epsilon n^{1/2} for n≥4n\ge4, where ϵ=n1/2−a\epsilon=n^{1/2}-a; this bounds xax_a and hence every later xix_i by 2n1/22n^{1/2}, and the total by 2n3/22n^{3/2}. Lower bound. The integer points (x,y)(x,y) with 0≤x,y≤a0\le x,y\le a, together with known estimates for the number of solutions of u2+v2=mu^2+v^2=m; the paper's footnote cites Erdős, J. London Math. Soc. 12 (1937), p. 133, and says the argument would rest on the prime number theorem for primes 4k+14k+1, or a weaker elementary result on their distribution.

Dependencies

Estimates for the number of representations of an integer as a sum of two squares (the footnote on p. 249).

Bears on

  • Problem 90: the problem asks whether nn points in the plane always have at most n1+O(1/log⁡log⁡n)n^{1+O(1/\log\log n)} pairs at distance 11. Theorem 2's lower bound is the grid construction showing that this order is attained, its upper bound is n3/2n^{3/2}, and the remark that g(n)<n1+εg(n)<n^{1+\varepsilon} seems likely is the paper's expectation.
  • Problem 1085: in the plane (d=2d=2, the problem's plane part), Theorem 2 bounds the largest number of unit-distance pairs among nn points by n1+c/log⁡log⁡n<f2(n)<n3/2n^{1+c/\log\log n}<f_2(n)<n^{3/2}.