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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (p. 248, Section 1). For nn points of the plane, f(n)f(n) is the minimum, over all planar sets of nn points, of the number of different distances the set determines. The paper notes f(3)=1f(3)=1 (the equilateral triangle), f(4)=2f(4)=2 and f(5)=2f(5)=2.

Theorem 1 (p. 248, quoted). "The minimum number f(n)f(n) of distances determined by nn points of a plane satisfies the inequalities"

(n−3/4)1/2−1/2≤f(n)≤cn/(log⁡n)1/2.(n-3/4)^{1/2}-1/2\le f(n)\le cn/(\log n)^{1/2}.

Here cc is a constant the paper does not specify.

Higher dimensions (p. 248, the paragraph closing Section 1). For nn points in kk-dimensional space, with f(n)f(n) the corresponding minimum, the paper states that "the same method yields" c1n1/k<f(n)<c2n2/kc_1n^{1/k}<f(n)<c_2n^{2/k}. No proof is written out and the constants are not specified.

The paper says (p. 248) that it has sought to improve Theorem 1 for many years without success.

Source. P. Erdős, On sets of distances of nn points, Amer. Math. Monthly 53 (1946), 248--250; Theorem 1 and its proof on p. 248. The copy read is identified on the source card.

Read depth. Claims checked: the statement, the setting and the kk-dimensional remark were read clause by clause on the page images, and the proof was followed. Nothing here is independently reviewed.

Proof pointer

P. 248. Lower bound. Take a vertex P1P_1 of the convex hull of the points. If the distances from P1P_1 to the other points take KK values and the most frequent of them occurs NN times, then KN≥n−1KN\ge n-1. The NN points at that distance lie on one semicircle about P1P_1, so their distances to the first of them are N−1N-1 distinct values. Hence f(n)≥max⁡(N−1,(n−1)/N)f(n)\ge\max(N-1,(n-1)/N), which is least when N(N−1)=n−1N(N-1)=n-1; this gives (n−3/4)1/2−1/2(n-3/4)^{1/2}-1/2. Upper bound. The integer points (x,y)(x,y) with 0≤x,y≤n1/20\le x,y\le n^{1/2} number at least nn, and their distances are of the form (u2+v2)1/2(u^2+v^2)^{1/2} with 0≤u,v≤n1/20\le u,v\le n^{1/2}; the number of integers up to 2n2n that are sums of two squares is less than cn/(log⁡n)1/2cn/(\log n)^{1/2}, which the paper takes from Landau's Verteilung der Primzahlen, vol. 2.

Dependencies

Landau's count of the integers up to xx that are sums of two squares (the paper's footnote, p. 248).

Bears on

  • Problem 89: the problem asks whether every nn points in the plane determine ≫n/log⁡n\gg n/\sqrt{\log n} distinct distances. The theorem's upper bound, from the integer grid, shows that this order could not be improved; its lower bound is (n−3/4)1/2−1/2(n-3/4)^{1/2}-1/2.
  • Problem 1083: the kk-dimensional remark gives c1n1/k<f(n)<c2n2/kc_1n^{1/k}<f(n)<c_2n^{2/k}, stated without proof; the problem asks, for d≥3d\ge3, whether the minimum is n2/d−o(1)n^{2/d-o(1)}, the exponent of the remark's upper bound.