Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Source. Theorem 2, p. 504, of Adrian Dumitrescu, On distinct distances from a vertex of a convex polygon, Discrete Comput. Geom. 36 (2006), 503--509, doi:10.1007/s00454-006-1262-y, as named on the source card; labels and pages are the print's own.
Statement
Setting. A finite set of points is in convex position if the points are the vertices of a convex polygon (p. 503). The distances from a point are those from to the other points of , as in the count of the concluding remarks (p. 508).
Theorem 2 (p. 504). "Let be a set of points in convex position in the plane. Then there exists a point such that the number of distinct distances from is at least ."
In the corpus's words: every convex -gon has a vertex that sees at least distinct distances to the other vertices. The paper compares it with Moser's bound (Theorem 1, p. 503), which it improves, and with Erdős's conjectured (p. 504), which the regular -gon would show to be best possible. For the bound equals ; for , and every it is smaller (arithmetic done here, not in the paper).
Read depth. Claims checked: the statement, the definitions it uses and the proof's structure were read clause by clause on the printed pages 503--508. Nothing here is independently reviewed.
Proof pointer
Section 2, pp. 504--508, in the corpus's words. Let be the smallest disk containing . If only two points of lie on its boundary they span a diameter, one closed half-disk holds at least points, and Moser's Lemma 1 (p. 505) gives at least distinct distances from an endpoint. Otherwise three boundary points form a triangle with no obtuse angle, and lies in the three caps cut off by its sides, holding points with .
Suppose every point sees at most distances, and count the isosceles triangles determined by , an equilateral one counted three times. Szemerédi's argument bounds , each segment being the base of at most two isosceles triangles. Lemma 2 (p. 506), that for points in convex position inside a closed cap cut off by the chord , labelled clockwise, the distances from to the points following it are distinct, and so are those to the points preceding it, gives Corollary 1 (p. 506): points in convex position inside a closed cap whose chord has both endpoints among them determine at most isosceles triangles. Hence many segments inside each cap are the base of at most one isosceles triangle, and with Cauchy--Schwarz this gives (inequality (5), p. 507). On the other side, assuming , the circles about each point carry two or three points in the extremal distribution, which gives (inequality (6), p. 508). Comparing (5) and (6) yields (p. 508).
Dependencies
Within the paper: Lemma 1 (Moser, p. 505), Lemma 2 and Corollary 1 (p. 506). Outside it: Moser's argument on the smallest enclosing disk and Szemerédi's isosceles-triangle count, both cited by the paper through Pach and Agarwal, Combinatorial Geometry (1995), pp. 206--208.
Bears on
- Problem 982: a lower bound for the problem's statement, which asks for distinct distances from some vertex of a convex -gon. The bound reaches exactly for and falls short for , and every ; the paper's concluding remarks (p. 508) list the statement as conjecture C1 and leave it open.
- Problem 1082: background. Points in convex position have no three on a line, so the theorem is a lower bound for that problem's second question restricted to sets in convex position; it says nothing about other sets with no three on a line, for which the paper recalls Szemerédi's (Theorem 3, p. 504), outlining its proof on p. 505.