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Source. Lemma 4.1, p. 3, of L. Martínez and E. Roldán-Pensado, Points defining triangles with distinct circumradii, Acta Math. Hungar. 145 (2015), no. 1, 136-141, doi:10.1007/s10474-014-0443-z; read in arXiv:1402.6276v1 (25 February 2014), the edition named on the source card. Pages are those of that edition.
Read depth. Claims checked: the statement was read clause by clause on the printed page, and the proof (pp. 3-4) was read for structure only. Nothing here is independently reviewed.
Statement
General position is the paper's: no four points on a line or circle.
Lemma 4.1 (p. 3, quoted). "Let be an irreducible algebraic curve of degree at most . Then for every integer there exists an integer such that the following holds: every set with points in general position contains a subset with points such that all its triples determine circles of distinct radii."
The paper calls the lemma a particular case of its main theorem (p. 3). The degree matches the curves of Theorem 1.1, to which the lemma is applied.
Proof pointer
Pages 3-4. Take a maximal subset of the points with all triples of distinct circumradii, , and assume by Theorem 1.2. Points on circles of the radii through two points of number at most . For two distinct pairs of , Bézout's theorem gives that either is an irreducible component of or the two curves meet in at most points; the first case would force , against . Hence , which gives .
Dependencies
Theorem 1.2 of the same paper and Bézout's theorem.
Bears on
- Problem 827: the lemma is the special case of the problem for point sets lying on one irreducible algebraic curve of degree at most , under the paper's general position condition. On its own it bounds for no general point set; it is the step that handles the case Erdős's 1978 argument leaves out.