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Statement

Here t(p)t(p) is the largest number of lines through exactly three points of a pp-point set, as defined on the Theorem 1 page.

Theorem 3 (p. 409). For every p≥3p\ge3,

t(p)≤⌊p3⌊p−12⌋⌋,t(p)\le\Bigl\lfloor\frac p3\Bigl\lfloor\frac{p-1}2\Bigr\rfloor\Bigr\rfloor,

with ⌊x⌋\lfloor x\rfloor for the print's [x][x], "the greatest integer ⩽x\leqslant x".

The graph Γ(A)\Gamma(\mathcal A) (p. 408), used again in Theorems 4--8. For a (p,t)(p,t)-arrangement A\mathcal A, Γ(A)\Gamma(\mathcal A) has the pp points as nodes, two of them adjacent exactly when no line of A\mathcal A contains both. A point on kk lines of A\mathcal A has valence p−1−2kp-1-2k, so every valence has the parity opposite to pp, and Γ(A)\Gamma(\mathcal A) has e=(p2)−3te=\binom p2-3t edges, that is t=((p2)−e)/3t=(\binom p2-e)/3 (the paper's (∗)(*)). Remark (6) (p. 420) notes that Coxeter calls Γ(A)\Gamma(\mathcal A) the Menger graph of A\mathcal A.

Read depth. Claims checked: the statement and its derivation were read clause by clause on the page images of the print. Nothing here is independently reviewed.

Proof pointer

Pp. 408--409. From (∗)(*) and e≥0e\ge0, t≤⌊(p2)/3⌋t\le\lfloor\binom p2/3\rfloor for all pp. For even pp every node has odd, hence positive, valence, so e≥p/2e\ge p/2 and t≤⌊p(p−2)/6⌋t\le\lfloor p(p-2)/6\rfloor. The theorem writes the two cases as one formula. The argument is purely combinatorial, which Theorem 9 uses to carry it to pseudolines.

Remark (7) (pp. 420--421) calls a purely combinatorial generalization of Theorem 3 the question of T(p)T(p), the largest number of triples on pp symbols with no pair in two triples. It records Kirkman's and Schönheim's values of T(p)T(p) (listed in Table I, p. 399) and says that Theorem 3 strengthens to t(p)≤T(p)t(p)\le T(p), with a pseudoline analogue of t(p)t(p) between them.

Source. S. A. Burr, B. Grünbaum and N. J. A. Sloane, The orchard problem, Geometriae Dedicata 2 (1974), 397--424, DOI 10.1007/BF00147569 (source card).

Bears on

  • Problem 669: in the problem's notation the theorem bounds f3(n)f_3(n) above by ⌊n3⌊n−12⌋⌋\lfloor\frac n3\lfloor\frac{n-1}2\rfloor\rfloor, which is the pair count for lines through exactly three points with a parity correction for even nn. It says nothing about F3(n)F_3(n), which also counts lines through more than three points.