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Statement

If θ/π∈Q\theta/\pi\in\mathbb Q, tan⁡θ\tan\theta is defined, and tan⁡2θ∈Q\tan^2\theta\in\mathbb Q, then tan⁡2θ∈{0,1/3,1,3}\tan^2\theta\in\{0,1/3,1,3\}.

Source and scope. Beeson–Laczkovich–Zhang, arXiv:2604.03609v3, Lemma 24, p. 12. Complete rewritten deduction from the following external result, stated as Lemma 23 in the source: if θ/π\theta/\pi and cos⁡θ\cos\theta are rational, then cos⁡θ∈{0,±1/2,±1}\cos\theta\in\{0,\pm1/2,\pm1\} (I. Niven, Irrational Numbers, 1967, Corollary 3.12, p. 41).

Proof

The identity cos⁡(2θ)=(1−tan⁡2θ)/(1+tan⁡2θ)\cos(2\theta)=(1-\tan^2\theta)/(1+\tan^2\theta) makes cos⁡(2θ)\cos(2\theta) rational. Apply the stated cosine theorem to 2θ2\theta. The value −1-1 is impossible when tan⁡θ\tan\theta is defined. For the four remaining values, solve tan⁡2θ=(1−cos⁡(2θ))/(1+cos⁡(2θ))\tan^2\theta=(1-\cos(2\theta))/(1+\cos(2\theta)) to obtain 1,1/3,3,01,1/3,3,0, respectively.

Bears on. Problem 633.