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Source. Theorem 1.2, p. 2, with the definitions (1.1) on p. 2, of Trevor D. Wooley, Sums of three cubes, II, Acta Arith. 170 (2015), 73--100, read in the arXiv version arXiv:1502.01944v1 named on the source card; labels and pages here are that version's.

Read depth. Claims checked: the statement and the definitions were read clause by clause on p. 2, Lemma 5.1 on p. 16 and the deduction on p. 24 for their structure; the computations of Section 7 were not checked. Nothing here is independently reviewed.

Statement

Let A(P,R)={n∈[1,P]∩Z:p∣n and p prime⇒p≤R}\mathcal A(P,R)=\{n\in[1,P]\cap\mathbb Z: p\mid n \text{ and } p \text{ prime}\Rightarrow p\le R\} be the RR-smooth numbers of size at most PP. With e(z)=e2πize(z)=e^{2\pi iz} put

f(α;P,R)=∑x∈A(P,R)e(αx3),F(α;P)=∑1≤x≤Pe(αx3)(1.1)f(\alpha;P,R)=\sum_{x\in\mathcal A(P,R)}e(\alpha x^3), \qquad F(\alpha;P)=\sum_{1\le x\le P}e(\alpha x^3) \qquad(1.1)

(p. 2).

Theorem 1.2 (p. 2). Write δ6=0.24871567\delta_6=0.24871567. Then there is a positive number η\eta such that, whenever R≤PηR\le P^\eta,

∫01∣F(α;P)2f(α;P,R)4∣ dα≪P3+δ6.(1.2)\int_0^1|F(\alpha;P)^2f(\alpha;P,R)^4|\,d\alpha\ll P^{3+\delta_6}. \qquad(1.2)

The paper compares (p. 2) the exponent δ6=0.24941301…\delta_6=0.24941301\ldots of the author's earlier work and δ6=14+ε\delta_6=\tfrac14+\varepsilon, any ε>0\varepsilon>0, from Vaughan's sixth moment for f(α;P,R)f(\alpha;P,R), and notes that applications need (1.2) with δ6<14\delta_6<\tfrac14. The same δ6\delta_6 is the s=6s=6 entry of Table 1 (p. 4), and Theorem 1.5 (p. 4) gives ∫01∣f(α;P,R)∣6 dα≪P3+δ6\int_0^1|f(\alpha;P,R)|^6\,d\alpha\ll P^{3+\delta_6} under that theorem's hypotheses (η>0\eta>0, PP sufficiently large in terms of η\eta, R≤PηR\le P^\eta).

Proof pointer

Section 7, p. 24, with Lemma 5.1 (p. 16). Lemma 5.1 shows that for real 4<t≤84<t\le8, if δ6≤23\delta_6\le\tfrac23 and δt≤16(t−4)\delta_t\le\tfrac16(t-4) are associated exponents (Section 2, p. 5: Ut(P,R)≪Pt/2+δt+εU_t(P,R)\ll P^{t/2+\delta_t+\varepsilon}), then the left side of (1.2) is ≪P3+δ6′+ε\ll P^{3+\delta_6'+\varepsilon} with δ6′=2max⁡{(8−t+8δt)/(24+t+8δt), δ6/(4+δ6)}\delta_6'=2\max\{(8-t+8\delta_t)/(24+t+8\delta_t),\ \delta_6/(4+\delta_6)\} (equations (5.1), (5.2)). The computed iteration of Section 7 gives, by convexity, the associated exponent δt=0.14963020\delta_t=0.14963020 at t=5.392938t=5.392938, and (5.2) then yields Theorem 1.2.

Dependencies

Lemma 5.1 and the computations of Section 7 of the same paper; Lemma 5.1 uses inequality (5.3) of T. D. Wooley, Breaking classical convexity in Waring's problem: sums of cubes and quasi-diagonal behaviour, Invent. Math. 122 (1995), 421--451 (the paper's reference [24]), and the argument of the author's earlier Sums of three cubes, Mathematika 47 (2000), 53--61 (reference [26]).

Bears on

  • Problem 325: only through Theorem 1.1, which the paper deduces from this estimate; that page states the relation.