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Statement
Lemma 4.3 (printed p. 5). " is powerful finitely often."
The lemma is one of the parts into which the paper breaks the proof of Theorem 4.1, so is the fixed integer of that theorem, and the statement is read as: for fixed , only finitely many make powerful. The lemma's statement does not mention the abc conjecture; its proof invokes it, so the lemma holds as proved only under the hypothesis of Theorem 4.1. The proof takes and uses , so it treats ; the case is Lemma 4.2.
Source. D. Cushing and J. E. Pascoe, Powerful numbers and the ABC-conjecture, arXiv:1611.01192v1 (3 November 2016); Lemma 4.3 on p. 5, its proof on pp. 5--6. The edition is identified in the source digest.
Read depth. Claims checked: the statement and the shape of the proof were read on the page images of the preprint; the inequalities were not checked step by step, and nothing here is independently reviewed.
Proof pointer
Pp. 5--6. For and with powerful, the proof divides through by and applies the abc conjecture with to the coprime triple . The radical of the product is at most , by (Lemma 2.5, p. 3) and the radical bound for powerful numbers (Lemma 2.6, p. 3, used in the form ). Because grows only exponentially in while , the triple satisfies for all large , which the abc conjecture allows only finitely often. The final display writes where the triple has .
Bears on
- Problem 936: with the lemma gives, assuming abc, that is powerful for only finitely many . This is the case of the problem, conditionally; the case is Exercise 4.4, left to the reader.
- Problem 398: every square is powerful, so the case also gives, assuming abc, only finitely many solutions of . The problem asks whether the known solutions are the only ones, which a finiteness statement does not answer; the paper's introduction (p. 2) recalls this finiteness as already shown under abc by Overholt (its reference [2]).