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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (p. 295). For a set A={ai}A=\{a_i\} of nonnegative integers, k(x)k(x) is the number of aia_i less than xx.

Problem 12 (p. 295). Erdős asks three questions.

  1. If every natural number nn has a representation n=ai+2jn=a_i+2^j, it is known (Lorentz, [36, Theorem 2] of the paper) that such a set AA exists with k(x)<cx(log⁡log⁡x)/log⁡xk(x)<cx(\log\log x)/\log x. Can the factor log⁡log⁡x\log\log x be dropped?
  2. There is a set {ai}\{a_i\} such that every natural number has a representation n=ai+pjn=a_i+p_j with pjp_j prime and k(x)<c(log⁡x)2k(x)<c(\log x)^2 (Erdős, [18, p. 847] of the paper). Can this be improved?
  3. Hanani's question (oral communication). Let {ai}\{a_i\} and {bj}\{b_j\} be two increasing sequences of natural numbers such that every nn has a representation n=ai+bjn=a_i+b_j. Is it true that (quoted) "lim sup⁡ka(x) kb(x)x>1\limsup \frac{k_a(x)\,k_b(x)}{x} > 1?" The paper does not define kak_a and kbk_b; by the setting above they count the terms of each sequence below xx.

The paper poses the three questions and resolves none of them.

Source. P. Erdős, Some unsolved problems, Michigan Math. J. 4 (1957), 291--300; §A, Problem 12, p. 295. The edition read is identified on the source card.

Read depth. Claims checked: the item was read clause by clause on the page images of the journal print. The two known constructions are cited, not proved here.

Dependencies

None.

Bears on

  • Problem 785: the problem takes Hanani's setting, with A+BA+B required to contain all large integers rather than every nn, and asks about the case A(x)B(x)∼xA(x)B(x)\sim x, where Hanani's lim sup equals 11: must A(x)B(x)−xA(x)B(x)-x then tend to infinity? The paper records only Hanani's question and does not resolve it.