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Statement

Lemma (p. 307, unnumbered). Let a1<⋯<at1a_1<\cdots<a_{t_1} be a sequence (of integers) for which the number of distinct sums ai+aja_i+a_j is at most t12−ct_1^{2-c}, and let α<c\alpha<c. Then the number of integers xx such that ai+aj=xa_i+a_j=x has at least t1αt_1^{\alpha} solutions is at least

2t+O(t1−(c−α)/2).2t+O\bigl(t^{1-(c-\alpha)/2}\bigr).

The print writes tt in the conclusion where the hypothesis has t1t_1; the proof works throughout with t1t_1 (it sets M=t11−(c−α)/2M=t_1^{1-(c-\alpha)/2} and reaches the count t1−3Mt_1-3M for one of two halves, p. 308), so tt there reads as t1t_1. The paper calls the lemma "perhaps of some independent interest" (p. 307). It places no explicit range on cc and α\alpha beyond α<c\alpha<c; Section 2 applies it with c=17/20c=17/20 and α=9/20\alpha=9/20 (p. 309).

Source. S. L. G. Choi, J. Komlós and E. Szemerédi, On sum-free subsequences, Trans. Amer. Math. Soc. 212 (1975), 307--313, DOI 10.1090/S0002-9947-1975-0376594-1; the Lemma on printed p. 307, its proof on pp. 307--308, read in the journal's printing. The paper and its edition are recorded on the source card.

Read depth. Claims checked: the statement and its hypotheses were read clause by clause on the page image. The proof was read for its structure and not checked.

Proof pointer

Pp. 307--308. With M=t11−(c−α)/2M=t_1^{1-(c-\alpha)/2}, the proof splits the sequence into its first MM terms S1S_1, its last MM terms S2S_2 and the rest S3S_3. Every integer of S2+S3S_2+S_3 has at most MM representations with the first summand in S2S_2, while the integers with fewer than t1αt_1^{\alpha} representations account for at most t12−ct1αt_1^{2-c}t_1^{\alpha} of the ∣S2∣∣S3∣|S_2||S_3| pairs; dividing the remaining pairs by MM gives at least t1−3Mt_1-3M integers of S2+S3S_2+S_3 with at least t1αt_1^{\alpha} representations. The paper states that S1+S3S_1+S_3 is handled in almost the same way and ends the proof there. Not reconstructed here.

Dependencies

None beyond counting.

Bears on

  • Problem 790: the Lemma is the tool of Section 2 of the paper, the proof of the upper bound f(n)≪n(log⁡n)−1f(n)\ll n(\log n)^{-1} in the Theorem; on its own it states nothing about the problem's l(n)l(n).