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Statement
An additive system is a family of sets of integers with and for all , such that the sums with for all and for only finitely many are exactly the nonnegative integers, and every nonnegative integer has exactly one such representation (p. 1).
Lemma 2 (p. 3). Let be an additive system, and let be a partition of into pairwise disjoint nonempty sets. If
for each , then is an additive system.
Definitions that follow it (pp. 3--4). A system obtained from in this way is a contraction of ; the paper notes that de Bruijn called it a degeneration. The index set may be finite or infinite. Every additive system is a contraction of itself, and taking and shows that the one-set system is a contraction of every additive system. A contraction is proper if at least one is the sum of at least two sets of .
Source. Melvyn B. Nathanson, Additive systems and a theorem of de Bruijn, Amer. Math. Monthly 121 (2014), no. 1, 5--17, doi:10.4169/amer.math.monthly.121.01.005, read in the arXiv version 1301.6208v2 (12 April 2013) identified on the source card, whose pages are numbered 1 to 12; labels and pages here are that version's. The lemma is on p. 3, the definitions after it on pp. 3--4.
Read depth. Claims checked: the statement and the definitions were read clause by clause on the page images of pp. 1, 3 and 4. Nothing here is independently reviewed.
Proof pointer
The paper gives no written proof; it says (p. 3) that the lemma follows immediately from the definition of an additive system. A representation of in the system expands, set by set, into a representation in , and conversely a representation in regroups along the blocks ; uniqueness in therefore gives uniqueness in .
Dependencies
None.
Bears on
- Problem 1145, as the source of a model case only. Applied to the binary system (the paper's Example 2, p. 2) with the positions split by parity, the lemma gives with the sums of distinct powers and ; the source card works out that the translates and give every exactly one representation while their th elements have ratio tending to , not . This derivation is the card's, not the paper's; the paper does not mention the problem, and the pair does not meet the problem's hypothesis .