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Source. Theorem 4, p. 5, of Greg Martin and Kevin O'Bryant, Constructions of Generalized Sidon Sets, J. Combin. Theory Ser. A 113 (2006), no. 4, 591-607, read in the arXiv edition arXiv:math/0408081v2 (21 Feb 2005) named on the source card.

Read depth. Claims checked: the statement and the definitions it uses were read clause by clause on the page images; the proof (Section 3.3, p. 14) was read for structure only. Nothing here is independently reviewed.

Statement

Setting (p. 2). S∗S(k)S*S(k) counts ordered pairs (s1,s2)∈S×S(s_1,s_2)\in S\times S with s1+s2=ks_1+s_2=k, ∥S∗∥∞=max⁡kS∗S(k)\lVert S^*\rVert_\infty=\max_k S*S(k), R(g,n)=max⁡{∣S∣:S⊆{1,…,n}, ∥S∗∥∞≤g}R(g,n)=\max\{\lvert S\rvert : S\subseteq\{1,\ldots,n\},\ \lVert S^*\rVert_\infty\le g\}, and σ(g)=lim inf⁡n→∞R(g,n)/⌊g/2⌋ n\sigma(g)=\liminf_{n\to\infty}R(g,n)/\sqrt{\lfloor g/2\rfloor\,n}.

Theorem 4 (p. 5). For g≥1g\ge1,

σ(2g+1)≥σ(2g)≥g+2⌊g/3⌋+⌊g/6⌋3g2−g⌊g/3⌋+g.\sigma(2g+1)\ge\sigma(2g)\ge \frac{g+2\lfloor g/3\rfloor+\lfloor g/6\rfloor}{\sqrt{3g^2-g\lfloor g/3\rfloor+g}}.

In particular, lim inf⁡g→∞σ(g)≥11/96\liminf_{g\to\infty}\sigma(g)\ge 11/\sqrt{96}.

The paper adds that 11/96>1.122611/\sqrt{96}>1.1226, against the authors' announced upper bound lim sup⁡g→∞σ(g)<1.8391\limsup_{g\to\infty}\sigma(g)<1.8391 from a work then in preparation (p. 5).

The right side exceeds 11 for every g≥12g\ge12 (a check made here: bounding g+2⌊g/3⌋+⌊g/6⌋≥(11g−13)/6g+2\lfloor g/3\rfloor+\lfloor g/6\rfloor\ge(11g-13)/6 and 3g2−g⌊g/3⌋+g≤(8g2+5g)/33g^2-g\lfloor g/3\rfloor+g\le(8g^2+5g)/3 reduces the claim to 25g2−346g+169>025g^2-346g+169>0, true for g≥14g\ge14, and g=12,13g=12,13 give 1.10551.1055 and 1.06321.0632). It also exceeds 11 for g=6,7,9,10g=6,7,9,10 and is below 11 for g≤5g\le5 and g=8,11g=8,11, where Theorem 3 gives the stronger bounds.

Proof pointer

Section 3.3 (pp. 13--14). The first inequality is the monotonicity R(2g+1,n)≥R(2g,n)R(2g+1,n)\ge R(2g,n). The second applies the bound σ(2g)≥R(g,x)/gx\sigma(2g)\ge R(g,x)/\sqrt{gx} from the proof of Theorem 3 with x=3g−⌊g/3⌋+1x=3g-\lfloor g/3\rfloor+1 and Theorem 2(vi). The paper records the sharper form

R(2g,n)≥11832gn(1+O(g−1+(n/g)(α−1)/2))R(2g,n)\ge\frac{11}{8\sqrt3}\sqrt{2gn}\Bigl(1+O\bigl(g^{-1}+(n/g)^{(\alpha-1)/2}\bigr)\Bigr)

as n/gn/g and gg both tend to infinity, where α<1\alpha<1 is any exponent such that for all large yy there is a prime between y−yαy-y^\alpha and yy, for instance α=0.525\alpha=0.525 by Baker, Harman and Pintz (p. 14); this gives the final assertion for even gg, and monotonicity gives it for odd gg.

Dependencies

Theorem 2 (ii), (v) and (vi), the prime number theorem, and, for the refined form, the Baker-Harman-Pintz theorem on primes in short intervals.

Bears on

  • Problem 863: with g=rg=r, the problem's largest B2[r]B_2[r] set in {1,…,N}\{1,\ldots,N\} has size R(2r,N)R(2r,N), and the theorem gives lim inf⁡NR(2r,N)/rN>1\liminf_N R(2r,N)/\sqrt{rN}>1 for every r≥12r\ge12 (and r=6,7,9,10r=6,7,9,10); with Theorem 3 for 2≤r≤112\le r\le11, this covers every r≥2r\ge2, so if ∣A∣∼crN1/2\lvert A\rvert\sim c_rN^{1/2}, then cr>rc_r>\sqrt r. The paper does not treat the difference sets BB of that problem or the constant cr′c_r'.