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If is an additive basis of order , and as , then must contain a minimal additive basis of order ? (i.e. such that deleting any element creates infinitely many )
What if (for all large , for arbitrary fixed )?
Source: erdosproblems.com/868
An accepted solution exists. The statement is false.
Disproved. The site labels the problem SOLVED (LEAN) and records a negative answer to both questions by Larsen and Larsen, who build a basis with representation counts above and no minimal subbasis, against the positive answer of [ErNa79] when every large has more than representations with in for some (the site writes this threshold for , which counts ordered pairs and is about twice that number); its label's Lean qualifier refers to a Lean 4 formalization of the note posted in lean-proofs on 2026-08-16, which this corpus has not audited. The accepted claim, a disproof of both questions, is Larsen and Larsen.