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We call a graph -balanced (or -almost-regular) if the maximum degree of is at most times the minimum degree of .
Is it true that for every , if is sufficiently large, any graph on vertices with edges contains a -balanced subgraph with vertices and edges (where the implied constants are absolute)?
Source: erdosproblems.com/803
An accepted solution exists. The statement is false.
Disproved. The site's label was DISPROVED on 2026-09-18; on 2026-10-07 the page printed no label to an anonymous reader, and the community database lists the problem as disproved (Lean), a status its file has carried since 26 September 2026. Alon's Proposition 2.1 ([Al08], Discrete Math. 308 (2008), no. 19, 4460--4472; refereed; author's preprint, p. 2): "For every and every , there is a graph with at most vertices and at least edges such that the following holds. For any and , if there is a subgraph of with vertices, average degree at least , and maximum degree at most , then ", introduced by "In this section we show that this is not true." A -balanced subgraph with vertices and average degree has maximum degree at most , so it has edges (a deduction made here), which is for fixed : no absolute works, whether is fixed and large or tends to infinity. The near-matching positive bound is Janzer and Sudakov's Theorem 6.3 (Forum Math. Pi 11 (2023), e19; refereed): given a positive integer , there are and for which each graph on vertices with or more edges contains a -almost-regular subgraph whose vertex count is at least and whose edge count is at least , so Alon's bound is tight up to factors. The frontmatter standing is derived from the accepted claim page Alon's disproof, whose acceptance evidence is the refereed journal, the refereed quotation by Janzer and Sudakov and the site's own commentary; Theorem 6.3 proves a weaker statement and settles nothing of the question, so it has no claim page.