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Alice and Bob play a game on the edges of , alternating colouring edges by red (Alice) and blue (Bob). Alice goes first, and wins if at the end the largest red clique is larger than any of the blue cliques.
Does Bob have a winning strategy for ? (Erdős believed the answer is yes.)
If we change the game so that Bob colours two edges after each edge that Alice colours, but now require Bob's largest clique to be strictly larger than Alice's, then does Bob have a winning strategy for ?
Finally, consider the game when Alice wins if the maximum degree of the red subgraph is larger than the maximum degree of the blue subgraph. Who wins?
Source: erdosproblems.com/778
No claim settles this problem.
Open. The site's label is OPEN. Two claims are recorded. Didin and Pimenov's potential argument, on its claim page (Didin and Pimenov, 2026), proves that the two-edge player wins the -biased game of the second question for every sufficiently large , with a Lean development naming the threshold ; Cambie confirmed the proof on the thread, so the page records it as an accepted partial claim. Cambie and Provoost's exhaustive search, on its claim page (Cambie Provoost, 2025), shows that Bob wins the unbiased game of the first question for and determines the maximum-degree game of the third question for (Alice wins for , Bob for ), a pending partial claim. No claim covers the first or third question for or the second question below the threshold, and the frontmatter standing is derived from the claim pages.