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Let be a graph with vertices and edges. Are there subgraphs such that has edges and every two edges in are contained in a cycle of length at most , and furthermore if two edges share a vertex they are on a cycle of length , and has edges and every two edges in are contained in a cycle of length at most .
Source: erdosproblems.com/584
No claim settles this problem.
Open, the site's label (OPEN), for a statement that no finite computation can settle; page last edited 22 January 2026. Under the reading the Formulation adopts, the first clause with is proved for no , and only with in place of for every (Duke, Erdős and Rödl 1984, Theorem 3), while the second clause is proved for every (Fox--Sudakov 2008, refereed) and claimed for every by a 2026 preprint announced on the thread [Li26] (Li 2026); the version of the first clause has been open since 1984. Under the fixed- reading both clauses are answered: the first by Duke and Erdős's Corollary 1 (1982), with the cubic dependence only as a remark of 1984, and the second by a result Duke, Erdős and Rödl state without proof in their 1992 paper [DER92], whose proof Fox and Sudakov attribute to a 1991 proceedings paper [DER91] that is not held. Three results concern ranges of bounded away from and settle no instance of the adopted question: Fox and Sudakov's remark that the second clause fails for close to , the girth-10 counterexamples of a note of 21 April 2026 posted on the thread [Ch26], which fail it for every , and the obstruction of [Li26] to the first clause for , . They are recorded in the Current assessment and have no claim pages; no result settles the first clause, so the standing derives as open.