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Let denote the size Ramsey number, the minimal number of edges such that there is a graph with edges that is Ramsey for .
If has vertices and maximum degree then prove that
Source: erdosproblems.com/559
An accepted solution exists. The statement is false.
Disproved, in the site's label (DISPROVED; page last edited 18 January 2026, accessed 2026-09-17). The statement fails for : Tikhomirov's Theorem 1.1 [Ti22b] gives, for every , an -vertex graph of maximum degree at most three with , which is not ; the arXiv version is the one accepted by Combinatorica, where the paper appeared in 2024 (refereed; the journal text was not compared). The original disproof is Theorem 1 of [RoSz00] (p. 258): positive constants and and a graph with and maximum degree such that , proved for with and . The statement holds for paths [Be83b], bounded-degree trees [FrPi87] and graphs of maximum degree two (cycles by [HKL95] and [JKOP19]; all such graphs through bounded treewidth, second-hand), so the failure begins at . How large can be for cubic graphs is open: between and [DrPe22]. The claim pages Rödl and Szemerédi 2000 and Tikhomirov 2022 record the two refereed disproofs with their postings and acceptance evidence; the frontmatter standing derives from these pages. The positive cases have partial claim pages: Beck 1983 (paths), Friedman and Pippenger 1987 (bounded-degree trees), Haxell, Kohayakawa and Łuczak 1995 (cycles) and Javadi, Khoeini, Omidi and Pokrovskiy 2017 (cycles, explicit constants). The bounded-treewidth result [KLWY21] has no claim page, since its statement is known here only through [DrPe22].