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Let and consider the set of numbers of the shape (for all finite ), ordered by size as .
Is it true that, provided is sufficiently small, ?
Source: erdosproblems.com/1096
An accepted solution exists. The statement is true.
The site's label is PROVED (LEAN), whose catalog suffix is explained under Formalization. The first resolution is Theorem IV of Erdős and Komornik's 1998 paper (Acta Math. Hungar. 79 (1998), 57--83, refereed), an accepted full claim on its page: "If and if is different from the square root of the second Pisot number, then for every ", where is the ordered sequence of the sums with digits and gives the problem's sequence; its introduction (p. 57) names the question as [EJK90]'s Problem 4 and says "One of the purposes of this paper is to give an affirmative answer to this question". With and (, the second Pisot number, the paper's ), every in is covered, so the answer is yes, with , and so is every in . Theorem 1.4 (i) of Akiyama and Komornik (J. Number Theory 133 (2013), 375--390, refereed; quoted from the arXiv text), the second accepted full claim, on their page, gives for every , a range that contains the excluded point and so closes it. A third first-hand source, the third accepted full claim, on Feng's page, is Theorem 1.4 of Feng's paper (J. Eur. Math. Soc. 18 (2016), 181--193, refereed; quoted from arXiv v3): for with not a Pisot number, . Since , the real root of , is the smallest Pisot number (Siegel's classical theorem, which the site's commentary also states), every in has not Pisot and , so the gaps tend to for every , with (an authored deduction, one line, from Feng's theorem and Siegel's theorem). The site reports the 1998 range as and Feng's introduction as "with the possible exception of the square root of the second Pisot number"; the printed theorem is Feng's version, and the site's range is its part below the excluded point. The frontmatter standing is derived from the three accepted pages; a fourth, pending claim, the thread's two-page note on Acosta De León's page, repeats the deduction from Feng's theorem and adds nothing to the standing.