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Let be a graph with girth (that is, it contains no cycles of length or ). Can the edges of always be directed such that there is no directed cycle, and reversing the direction of any edge also creates no directed cycle?
Source: erdosproblems.com/1006
An accepted solution exists. The statement is false.
Disproved. Corollary 3 of Nešetřil and Rödl [NeRo78b] (Proc. Amer. Math. Soc. 72 (1978), 417--421; refereed) gives, for every , a graph with no cycle of length less than which under every ordering of its vertices contains a monotone path , , closed into an -cycle by the edge . With this is a graph of girth five with no orientation of the required kind; the deduction is written out below and is this page's own. Corollary 4 of the same paper states the Hasse-diagram form. The paper describes its result as "the full solution of an Erdös-Ore problem" and cites Erdős's 1971 list for the question. The claim page Nešetřil and Rödl 1978 records the result, its postings and the acceptance evidence. O. Pretzel, "A non-covering graph of girth six" (Discrete Math. 63 (1987), 241--244; stated from its zbMATH summary and pending), constructs a graph of girth six that is not a cover graph, an explicit negative answer through the equivalence in the Formulation, recorded on Pretzel 1987. The standing in the frontmatter is derived from the claim pages.